How Do You Calculate Resultant Displacement for Two Interfering Waves?

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Homework Help Overview

The discussion revolves around calculating the resultant displacement of two interfering waves described by their mathematical equations. The waves have the same period, and the original poster seeks to find the resultant displacement at a specific time.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the addition of wave functions and the implications of phase differences. Questions arise about the correct interpretation of phase constants and the relationship between cosine terms. There is also a focus on understanding the superposition principle and whether subtraction is necessary for the given wave functions.

Discussion Status

Participants are exploring different interpretations of the wave equations and their phase relationships. Some guidance has been offered regarding resolving cosine terms and the implications of phase differences, but no consensus on a specific method has been reached.

Contextual Notes

There is an ongoing discussion about the definitions and relationships of the cosine function, as well as the implications of the waves being out of phase. The original poster expresses confusion about the calculations and the terminology used in the discussion.

roam
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Homework Statement



Two displacement waves with the same period T = 3.0 s are described mathematically by:

y1 = (10.0 m) cos[2πt/T + π]
y2 = (9.0 m) cos[2πt/T + 2π]

What is the resultant displacement at time t = 6.0 s?

The Attempt at a Solution



I tried adding up

y1 + y2 = 19 cos [2πt/T + 3π]

But the answer I get is wrong. I also tried the following formula from my texybook which is supposed to give the resultant of two traveling sinusoidal waves:

y=2Acos \left( \frac{\phi}{2} \right) sin \left( kx-\omega t + \frac{\phi}{2} \right)

I don't know what the phase constant (φ) is, so I assume it is zero since the waves are in phase, then cos(φ/2)=cos(0)=1.

When I plug in the numbers the formula then becomes

y=6sin(3π+2π6/3)

Again, this produces the wrong answer, the correct answer should be -1.0 m. What's wrong with my calculations? :confused:
 
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roam said:

Homework Statement



Two displacement waves with the same period T = 3.0 s are described mathematically by:

y1 = (10.0 m) cos[2πt/T + π]
y2 = (9.0 m) cos[2πt/T + 2π]

What is the resultant displacement at time t = 6.0 s?

The Attempt at a Solution



I tried adding up

y1 + y2 = 19 cos [2πt/T + 3π]

:


You can not do that! Try to think instead of plugging into equations you do not understand.

Resolve the cosine terms. What is the relation between cos(x) and cos(x+2π)? between cos(x) and cos(x+π)?


ehild
 


ehild said:
You can not do that! Try to think instead of plugging into equations you do not understand.

Resolve the cosine terms. What is the relation between cos(x) and cos(x+2π)? between cos(x) and cos(x+π)?


ehild

Does this mean that they are out of phase? I think if one wave has phase constant φ=(2N)π and the other wave has φ=(2N+1)π, where N is any integer, then the two waves are not in phase, and therefore destructive interference occurs.

What do you mean by "resolving" the cosine terms? :rolleyes:

The "superposition principal" states that the resultant value of the wave functions of the wave function at any point is the algebraic sum of the values of the wave functions of the individual waves. This is what I was trying to do, in my problem do I need to somehow subtract thw two given wave functions?
 


roam said:
What do you mean by "resolving" the cosine terms? :rolleyes:

Well, my English is poor, especially in maths expressions. I meant to express both cos[2πt/T + π] and cos[2πt/T + 2π] with cos (2πt/T). Think of the definition of the cosine function.

And you are right, y1 and y2 are out of phase.

If you still do not get it, just plug in 6.0 s for t, calculate both y1 and y2 and add them.

ehild
 

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