How Do You Calculate Stopping Distance Using a Velocity-Time Graph?

[getfirefox]

Hello everybody, I have a small question I need help with.

Homework Statement

Draw a sketch graph of the following:

"A car which is traveling at 15 ms-1. At t (time) = 0, the driver sees a pedestrian step out into the road. The driver takes 0.7 seconds to apply the brakes, and the brakes produce an acceleration of -6ms-2, bringing the car to a rest."

Use the stetch graph to calculate the stopping distance.

Homework Equations

None.

The Attempt at a Solution

None. Can somebody give me an example of what the graph would look like and how I would calculate the stopping distance. I take it this would be the displacement, or area under the line on the graph.

Thanks everyone.

 

[tiny-tim]

Draw a sketch graph of the following:

"A car which is traveling at 15 ms-1. At t (time) = 0, the driver sees a pedestrian step out into the road. The driver takes 0.7 seconds to apply the brakes, and the brakes produce an acceleration of -6ms-2, bringing the car to a rest."

Use the stetch graph to calculate the stopping distance.
…
Can somebody give me an example of what the graph would look like and how I would calculate the stopping distance. I take it this would be the displacement, or area under the line on the graph.

Hello getfirefox!

You should plot speed against time.

Constant speed is a horizontal line.

Constant deceleration is a straight line sloping down.

And yes, the stopping distance will be the area under the line.