How Do You Calculate Stopping Distances and Projectile Motion?

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SUMMARY

The discussion focuses on calculating stopping distances for an automobile and the time of flight for a projectile. To determine stopping distances, the initial speed of 91 km/h and human reaction time of 3.0 seconds are used with two different deceleration values: -4.0 m/s² and -8.0 m/s². The stopping distance is calculated using the equation x1 = v * tr for the distance before deceleration and a kinematic equation for the distance during deceleration. For projectile motion, a football kicked at 20.0 m/s at a 38.0° angle requires resolving components and applying kinematic equations to find the time until it hits the ground.

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of projectile motion concepts
  • Familiarity with acceleration and deceleration calculations
  • Basic trigonometry for resolving components
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  • Study the kinematic equations for linear motion
  • Learn how to calculate projectile motion using trigonometric functions
  • Explore the effects of reaction time on stopping distances
  • Review the principles of acceleration and deceleration in physics
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Students preparing for physics exams, educators teaching mechanics, and anyone interested in understanding motion calculations in real-world scenarios.

thschica
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Studying for exams need help very soon!

On both of these I got the right answer but it was so long ago I have no idea how to do them.
(Which equation am I to use?)(v=Vo+at? if so how?)
1.Determine the stopping distances for an automobile with an initial speed of 91 km/h and human reaction time of 3.0 s for the following accelerations.
(a) a = -4.0 m/s2
? m
(b) a = -8.0 m/s2
? m
(This one is beyond me I keep attempting to use equations but none of them are working)
2.5. A football is kicked at ground level with a speed of 20.0 m/s at an angle of 38.0° to the horizontal. How much later does it hit the ground?
? seconds
 
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a) use a kinematic equation to solve for "d"
, then use a kinematic equation to solve for "time"
then add reaction time.

b) resolve the components (sin & cos)
the y component give you time
 
The stopping distance consists of two parts, the distance traveled before the deceleration is applied, which is given by x1 = v tr, where r would be the response time, and then the distance traveled during the period of deceleration, which is governed by a different equation.

see - http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#mot1
for linear motion in one dimension.
 

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