How Do You Calculate Tension in a Cable and Compression in a Brace?

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SUMMARY

The discussion focuses on calculating the tension in a cable and the compression in a brace supporting a 235lb sign, with the cable inclined at 37 degrees to the horizontal. The calculated values are 390.5 lbs for tension and 311.9 lbs for compression. Participants emphasize the importance of using a free body diagram to identify forces, including the weight of the sign, cable tension (with both x and y components), and brace compression (x component only). Newton's first law is applied to solve for these components.

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  • Familiarity with Newton's laws of motion
  • Basic trigonometry for angle calculations
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Students in physics or engineering courses, particularly those studying statics and dynamics, as well as anyone needing to understand tension and compression in structural applications.

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Homework Statement


A 235lb sign is supported from a wall by a cable inclined 37 degrees with the horizontal, and a brace perpendicular to the wall. Find the tension in the cable and the compression in the boom.

The answers are 390.5 and 311.9. But I have no idea how they got to those numbers. :S

Homework Equations


No idea?


The Attempt at a Solution



Tried to find the x/y components of the vectors, but I'm confused now.
 
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copyfilew said:

Homework Statement


A 235lb sign is supported from a wall by a cable inclined 37 degrees with the horizontal, and a brace perpendicular to the wall. Find the tension in the cable and the compression in the boom.

The answers are 390.5 and 311.9. But I have no idea how they got to those numbers. :S

Homework Equations


No idea?


The Attempt at a Solution



Tried to find the x/y components of the vectors, but I'm confused now.
One way is to draw a free body diagram of the sign and identify the forces acting on it ...its weight down, the cable tension along the length of the cable (which has an x and a y component), and the brace compression along its length (x component only). Then use Newton 1 inthe x and y direction to solve for the components.
 

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