How Do You Calculate Tension in Violin Strings?

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The discussion centers on calculating the tension in violin strings based on a physics problem involving four strings, a total normal force of 103N, and an angle of 72 degrees with the normal. The original poster's calculation led to a tension of 41.7N, which does not match the textbook answer of 34.4N. A participant suggests that the discrepancy may arise from the angle being interpreted incorrectly, indicating that the angle should be 18 degrees above horizontal instead. The poster seeks further clarification and assistance with subsequent parts of the problem regarding forces and work done. Accurate interpretation of angles and forces is crucial for resolving the tension calculation.
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I wanted to ask for some help, but first a little about me. I am a physician, but my major was mathematics many years ago. Currently, I am reviewing physics "for the fun of it" and I'm using Tipler's text for review. In the newest edition, I am trying to work problem 77 in chapter 6, but I can't seem to get an answer that agrees with the back of the text. The question is as follows:

The four strings pass over the bridge of a violin so that the strings make an angle of 72 degrees with the normal to the plane of the instrument on either side. The total normal force pressing the bridge into the violin is 103N. The length of the strings from bridge to the peg ot which each is attached is 32.6 cm.
(a) Determine the tension in the violin strings, assuming that the tension is the same for each string.
(b) One of the strings is plucked out a distance of 4mm. Make a free-body diagram showing all of the forces acting on the string at that point, and determine the force pulling the string back to its equilibrium position. assume that the tension in the string remaings constant.
(c) Determine the work done on the string in plucking it out that distance.

Answers as given in back of book: (a) 34.4 N; (b) 1.68N; (c) 3.38mJ

My reasoning: 4 total strings; therefore each strings exerts a force of 103N/4=25.75N downward on the bridge. 2Tsin18=25.75, so T=41.7N.

I gave up working the rest since I can't even get this answer to agree. Would someone be kind enough to enlighten this rusty doc and maybe even give me a start on part's b and c?
 
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hunchback6116 said:
I wanted to ask for some help, but first a little about me. I am a physician, but my major was mathematics many years ago. Currently, I am reviewing physics "for the fun of it" and I'm using Tipler's text for review. In the newest edition, I am trying to work problem 77 in chapter 6, but I can't seem to get an answer that agrees with the back of the text. The question is as follows:

The four strings pass over the bridge of a violin so that the strings make an angle of 72 degrees with the normal to the plane of the instrument on either side. The total normal force pressing the bridge into the violin is 103N. The length of the strings from bridge to the peg ot which each is attached is 32.6 cm.
(a) Determine the tension in the violin strings, assuming that the tension is the same for each string.
(b) One of the strings is plucked out a distance of 4mm. Make a free-body diagram showing all of the forces acting on the string at that point, and determine the force pulling the string back to its equilibrium position. assume that the tension in the string remaings constant.
(c) Determine the work done on the string in plucking it out that distance.

Answers as given in back of book: (a) 34.4 N; (b) 1.68N; (c) 3.38mJ

My reasoning: 4 total strings; therefore each strings exerts a force of 103N/4=25.75N downward on the bridge. 2Tsin18=25.75, so T=41.7N.

I gave up working the rest since I can't even get this answer to agree. Would someone be kind enough to enlighten this rusty doc and maybe even give me a start on part's b and c?
Your answer is correct if the angle is 18 degrees above horizontal. Text book answers are not always right.

AM
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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