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## Homework Statement

Two blocks are connected by a massless string that passes over a frictionless pulley. The coefficient of static friction between m1 and the table is 0.45. The coefficient of kinetic friction is 0.35. Mass m1 is 45kg and mass m2 is 12kg. Determine tension in the string. ***I attached a picture of the diagram provided with the question.

## Homework Equations

Fnet=ma

μ

_{s}F

_{N}=F

_{s}

## The Attempt at a Solution

I thought that (Fnet)x=0 for m1 since this system is not in motion- it's in static equilibrium. I worked with the forces acting on m1, assuming that Fnet=0 for m1.

So, (Fnet)x=Fs+Ft

0=μ

_{s}F

_{N}+Ft

-(0.45)(mg)=FT

-(0.45)[(45)(9.80]=Ft

-198.45N=Ft

The answer in the back of the book is 120N. What did I do wrong?

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