How Do You Calculate Terminal Voltage Vab in a Circuit?

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Homework Help Overview

The discussion revolves around calculating the terminal voltage Vab in a circuit involving a 12.0V battery and various resistors. Participants are exploring the implications of current measurements and resistor configurations within the circuit.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply Kirchhoff's rules and Ohm's law to find the terminal voltage, while others question the treatment of resistors and the calculations involving internal resistance.

Discussion Status

Participants are actively questioning the assumptions made regarding resistor configurations and the calculations performed. Some guidance has been provided regarding the combination of resistors, but there is no explicit consensus on the correctness of the original poster's approach.

Contextual Notes

There is a mention of a missing 30-ohm resistor and its relevance to the calculations, which may affect the overall understanding of the circuit setup.

rizardon
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Homework Statement


In the circuit shown in the figure below the current through the 12.0V battery is measured to be 70.6 mA in the direction shown. What is the terminal voltage Vab



Homework Equations


V=E-IR
I1=I2+I3


The Attempt at a Solution


First I set Vab= E-IR= 24 - 10(I1)
I1=I2 + I3
So I applied Kirchoff's rule on the outer loop to find I3
-12 - 10I2 + 20I3 = 0
I3= [12 + 10I2]/20 = 0.6000353 = 0.6A
I1= I2 + I3 = 70.6 mA + 0.6A = 0.6000706A = 0.6A
Vab= 24 -10I1 = 24 - 6 = 18V
Is this right?
 

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What happened to the 30-ohm resistor?

The voltage due to the internal resistance of the 12-volt battery is (70.6 mA)(10 ohms) = 706 mV = 0.706 V. You seem to have divided by another factor of 1000.
 
Can I combine the 20(ohm) with the 10(ohm) resistor?
 
No, because they're neither in series nor in parallel. You could, however, combine the 20-ohm and 30-ohm resistors because they're in parallel.
 

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