How Do You Calculate the Amplitude of Forced Oscillation in SHM?

  • Thread starter Thread starter ronny45
  • Start date Start date
  • Tags Tags
    Mass Shm String
Click For Summary
SUMMARY

The discussion focuses on calculating the amplitude of forced oscillation in a simple harmonic motion (SHM) system involving a 2 kg mass attached to a spring. The spring extends by 2.5 cm when the mass is attached, and the system oscillates with an amplitude of 1 mm. The angular frequency (w_0) is calculated to be 0.495 radians/sec using the formula (w_0)^2 = k/m, where k is derived from the gravitational force. The quality factor (Q) is given as 15, leading to a damping coefficient (gamma) of 0.016, indicating heavy damping in the system.

PREREQUISITES
  • Understanding of simple harmonic motion (SHM)
  • Familiarity with Hooke's Law and spring constants
  • Knowledge of angular frequency and damping in oscillatory systems
  • Ability to manipulate equations involving forces and oscillations
NEXT STEPS
  • Learn about the relationship between damping and amplitude in forced oscillations
  • Study the effects of varying the quality factor (Q) on oscillatory systems
  • Explore the derivation and application of the equation x=Acos(w_0*t + phi)
  • Investigate the implications of heavy damping on the behavior of oscillating systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and oscillations, as well as educators looking for examples of SHM and forced oscillation calculations.

ronny45
Messages
20
Reaction score
0

Homework Statement



A 2 kg object hangs from a spring, the mass of which can be discounted. When the object is attached, the spring extends by 2.5cm. The top of the spring is then oscillated up and down in SHM with an amplitude of 1mm. If Q=15 for the system, find w_0 (angular frequency) and the amplitude of the forced oscillation at w=w_0.

Homework Equations



F=-kx, F=mg
(w_0)^2=k/m
x=Acos(w_0*t + phi)
Q=w_0/gamma, where gamma is the width.

The Attempt at a Solution



Setting the gravitational force equal to the restoring force gives mg=-kx, rearranging gives (w_0)^2=k/m=-x/g=(0.025m)(9.81m s^-2)=0.245m^2 s^-2

Using that value for w_0 and the given one for Q I found gamma to be 0.016. Since this is less that 2w_0, there's heavy damping. Not sure how to progress from there, the fact that amplitude's involved i think i need x=Acos(w_0*t + phi), but how to deal with the time and phase difference? Any push in the right direction would be appreciated.
 
Physics news on Phys.org
ronny45 said:
Setting the gravitational force equal to the restoring force gives mg=-kx, rearranging gives (w_0)^2=k/m=-x/g=(0.025m)(9.81m s^-2)=0.245m^2 s^-2

Using that value for w_0 and the given one for Q I found gamma to be 0.016. Since this is less that 2w_0, there's heavy damping. Not sure how to progress from there, the fact that amplitude's involved i think i need x=Acos(w_0*t + phi), but how to deal with the time and phase difference? Any push in the right direction would be appreciated.

First: I'm concerned about your units in w_0 (which is supposed to be a radial frequency, therefore it should have unit of radians/sec...)
 
I see what you mean, I was just trying to be consistent with the units on the RHS without thinking of the quantity involved.
 

Similar threads

Replies
39
Views
5K
  • · Replies 1 ·
Replies
1
Views
8K
Replies
9
Views
2K
Replies
5
Views
2K
Replies
3
Views
1K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K