How Do You Calculate the Angle of Incline with Friction Involved?

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SUMMARY

The discussion focuses on calculating the angle of incline when friction is involved, specifically for a body weighing 50N that requires a force of 35N to ascend the incline with a coefficient of friction of 0.25. The equation used is F = W sin a + u W cos a, leading to the equation 35N = 50N*sin a + 0.25*50N*cos a. Participants suggest using graphing techniques or spreadsheet formulas to isolate the angle "a" and recommend employing trigonometric identities and the unit circle for a more analytical approach to solve the problem.

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Homework Statement


On a certain incline plane, a body weighs 50N and requires a force of 35N to pull it up the incline. If the coefficient of friction is 0.25, find the angle of incline. (in degrees)

I've been stuck on this for two days now.

Homework Equations


F=W sin a + u W cos a


The Attempt at a Solution


35N= 50N*sin a + 0.25*50N*cos a

I'm not sure how to isolate for "a".
 
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I don't know how to isolate "a" either, but you can certainly find the answer to any desired accuracy. You could graph the y = 50N*sin a + 0.25*50N*cos a on your calculator and see where it intersects y = 35. Or put it in a spreadsheet formula and try various values for a until you get an answer of 35.

An interesting approach is to use the method of solving triq equations where you replace cos a with x and sin a with y. This gives a linear equation of the form y = mx + b which you can easily graph. Also graph the unit circle. The intersections of the line and circle are the x,y solutions and the angle counterclockwise from the x-axis is the solution for angle a. You can actually solve this without using the graph if you write x² + y² = 1 for the unit circle and then solve the two equations simultaneously (solve the linear one for y and sub into the circle equation). You end up with a quadratic equation that you can solve to get x and then use x = cos(a) to find the value of a.
 

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