How Do You Calculate the Arc Length of a Baseball's Trajectory?

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SUMMARY

The discussion focuses on calculating the arc length of a baseball's trajectory using parametric equations. The equations derived are x = 146.7cos(theta)t and y = 3 + 146.7sin(theta)t - 16t^2, where theta is the launch angle and the initial speed is 100 mph. The arc length formula is established as L = ∫√(dx² + dy²), with integration limits defined by the time of flight T. The angle theta is suggested to be 15 degrees based on previous calculations, but it can also remain as a variable.

PREREQUISITES
  • Understanding of parametric equations in physics
  • Knowledge of calculus, specifically integration techniques
  • Familiarity with projectile motion concepts
  • Ability to graph mathematical functions
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  • Study the derivation of the arc length formula in calculus
  • Learn how to calculate the time of flight for projectile motion
  • Explore the impact of different launch angles on projectile trajectories
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calcboi
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The centerfield fence at a ballpark is 10 ft high and 400 ft from home plate. The ball is 3 ft above the ground when hit, and leaves with an angle theta degrees with the horizontal. The bat speed is 100 mph. Use the parametric equations x = (v0cos(theta))t y = h + (v0sin(theta))t - 16t^2
a. Write parametric equations for the path of the ball.
I got this as x = 146.7cos(theta)t and y = 3 + 146.7sin(theta)t - 16t^2
b. Graph the path of the ball if theta = 15 degrees. Is it a home run?
I got no because the ball only reached 349 ft, not 400 ft.
c. Find the arc length of the path of the ball until it lands.
This is the part I need help on. I don't know how to get the arc length.
 
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calcboi said:
The centerfield fence at a ballpark is 10 ft high and 400 ft from home plate. The ball is 3 ft above the ground when hit, and leaves with an angle theta degrees with the horizontal. The bat speed is 100 mph. Use the parametric equations x = (v0cos(theta))t y = h + (v0sin(theta))t - 16t^2
a. Write parametric equations for the path of the ball.
I got this as x = 146.7cos(theta)t and y = 3 + 146.7sin(theta)t - 16t^2
b. Graph the path of the ball if theta = 15 degrees. Is it a home run?
I got no because the ball only reached 349 ft, not 400 ft.
c. Find the arc length of the path of the ball until it lands.
This is the part I need help on. I don't know how to get the arc length.

Hi calcboi!

You can find the formula for arc length here on wiki.

In short the arclength L is:
$$L=\int ds = \int \sqrt{dx^2 + dy^2} = \int \sqrt{(x'(t)dt)^2 + (y'(t)dt)^2} = \int \sqrt{x'(t)^2 + y'(t)^2}dt$$
 
Thanks, but I am unsure what to use for the limits of integration.
 
calcboi said:
Thanks, but I am unsure what to use for the limits of integration.

Did you find the time at which the ball lands?
Let's call that T.
Then the integral limits are t=0 and t=T.
 
I like Serena said:
Did you find the time at which the ball lands?
Let's call that T.
Then the integral limits are t=0 and t=T.

I can't find T unless I have an angle for theta, and I don't know what to put for the angle. I am guessing I should use 15 degrees from the earlier portion but I'm not sure.
 
calcboi said:
I can't find T unless I have an angle for theta, and I don't know what to put for the angle. I am guessing I should use 15 degrees from the earlier portion but I'm not sure.

I'm also guessing you should probably use 15 degrees from the earlier question.
But you can also leave it as just theta and treat it as an arbitrary constant which just happens to have an unknown value.
 

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