jevanuD Messages 11 Reaction score 0 Thread starter Mar 30, 2018 #1 View attachment 8012 Attachments Sector Question.JPG 19.2 KB · Views: 188
skeeter Messages 1,103 Reaction score 1 Mar 30, 2018 #2 area of region ABCD ... $A = \dfrac{\theta}{2}\left(R^2-r^2\right)$ you have $R = 3k$, $r=2k$, and $\theta = \dfrac{3}{4}$ ... proceed to solve for $k$ also, arc length difference is $\Delta s = \theta(R - r)$
area of region ABCD ... $A = \dfrac{\theta}{2}\left(R^2-r^2\right)$ you have $R = 3k$, $r=2k$, and $\theta = \dfrac{3}{4}$ ... proceed to solve for $k$ also, arc length difference is $\Delta s = \theta(R - r)$