How Do You Calculate the Coefficient of Friction on an Inclined Slide?

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SUMMARY

The discussion focuses on calculating the coefficient of friction for a child's slide inclined at 25 degrees, with a mass of 35 kg. The normal reaction force was correctly calculated as 311 N. Since Matthew descends the slide at a constant speed, the acceleration is zero, leading to the conclusion that the frictional force equals the component of gravitational force acting down the slide. The coefficient of friction can be determined using the equation F = μR, where R is the normal force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of basic trigonometry, particularly sine functions
  • Familiarity with the concept of normal force in physics
  • Ability to manipulate equations involving friction and forces
NEXT STEPS
  • Learn how to derive the coefficient of friction using F = μR
  • Study the effects of incline angles on frictional forces
  • Explore the relationship between mass, weight, and normal force
  • Investigate real-world applications of friction in inclined planes
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Students studying physics, particularly those focusing on mechanics and forces, as well as educators looking for practical examples of friction calculations.

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Homework Statement



1. A childs slide is straight and inclined at 25o to the horizontal. Matthew of mass 35kg goes down the slide at a constant speed.

(a) draw a diagram
(b) find the magintude of normal reaction force between matt and slide.
(c) Find the coefficient of friction between matt and the slide

part (a) and (b) are fine i got 311N for part (b) but couldn't find (c)


Homework Equations



F = MA
F = ,U (mew) x R


The Attempt at a Solution



Resolved it in direction of friction got;

Fr - 35gsin25 = 35a
could not do this as had two unknowns
same with
F = mew x 311 and F = 35a

any help would be greatly appreciated!
 
Physics news on Phys.org
Matthew of mass 35kg goes down the slide at a constant speed.

What does that imply about the value of the acceleration?
 
it implies that the acceleration is zero, i see now, thanks very much for your help :)
 

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