How Do You Calculate the Damping Coefficient of a Pendulum in Water?

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SUMMARY

The discussion focuses on calculating the damping coefficient (C) of a pendulum submerged in water, given parameters such as mass (M=1kg), length (L=1.0m), and period (T=2.02sec). The equation of motion is defined as θ'' + (c/m)θ' + (g/l)θ = 0, where g represents gravitational acceleration. Participants emphasize the importance of using the correct equations and methods to derive the damping coefficient, rather than relying on unrelated formulas like the half-life equation T(1/2) = LN(2)/λ.

PREREQUISITES
  • Understanding of differential equations, specifically second-order linear equations.
  • Familiarity with pendulum dynamics and the effects of damping in oscillatory systems.
  • Knowledge of gravitational acceleration (g) and its role in pendulum motion.
  • Basic proficiency in mathematical notation, including the use of θ (theta) and λ (lambda).
NEXT STEPS
  • Research methods for solving second-order linear differential equations, particularly in the context of damped oscillations.
  • Explore the relationship between damping coefficients and oscillation periods in fluid environments.
  • Learn about the physical principles governing pendulum motion in different mediums, such as water.
  • Study the derivation and application of the natural frequency (Wn = sqrt(g/L)) in damped systems.
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Students and professionals in physics, engineering, and applied mathematics who are interested in understanding the dynamics of damped oscillatory systems, particularly pendulums in fluid environments.

math111
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I am giving M=1kg, L=1.0m, T(period) = 2.02sec. I need to find C

The pendulum is in water.

The eq of motion is double-dot-theta+(c/m)single-dot-theta+(g/l)theta = 0

I was doing some research and found this half life formula...T(1/2) = LN(2)/ Lamda. I am not sure where to go from here...

I know Wn = sqrt(g/L)...
 
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math111 said:
I am giving M=1kg, L=1.0m, T(period) = 2.02sec. I need to find C

The pendulum is in water.

The eq of motion is θ'' + (c/m)θ' + (g/l)θ = 0

I was doing some research and found this half life formula...T(1/2) = LN(2)/λ. I am not sure where to go from here...

I know Wn = sqrt(g/L)...

Hi math111! :smile:

(have a theta: θ and a lamda: λ and use ' instead of dot :smile:)

hmm … I'm don't think that T(1/2) is the same T that you were given. :confused:

It is not a good idea to trawl the web looking for an equation that might fit. :frown:

Hint: do you know any method of solving θ'' + (c/m)θ' + (g/l)θ = 0 ? :smile:
 

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