How Do You Calculate the Damping Constant of a Hard-Boiled Egg on a Spring?

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a 50 g Hard Boiled egg moves on the end of a spring with force constant k=25N/m. Its intial displacement is .3m. A damping force F=-bv acts on the egg and the amplitude of the motion decreases to .1 m in 5 sec. Calculate the magnitue of the damping contant b.

How exactly do you go about doing this?
I haven't been able to get anywhere on it.
 
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Start with the solution of the equation of motion for this system.
 
so we have

x=Ae^-(b/2m)t cos(w't+phi)

where w'=(k/m -b^2/4m^2)^1/2

so here's the problem do you use the initial conditions to solve for b or the final positions, does it make a difference?
 
Before you can solve for b you have to apply the initial conditions to solve for A beforehand. Just assume phi is 0.

Once you have the value for A, solve for b using the other informations given (btw, don't assume that those are for the final position).
 
isnt A=.3 since that's the starting position
i put it into a function solver and i got
2.94587866888,

does that seem right?

also i didnt use the .1 if i was suppose too
 
:smile: Lol...I advise you to analytically or numerically solve this problem as I doubt your teacher would accept your answer. I admit solving for b is a bit tedious but you already got A! Keep on working...

Also usually [itex]0\leq b\leq 1[/itex].

Hint: Work with the amplitude of oscillation component of your equation instead of working with the whole thing.
 
ok so ignoring the cos stuff i got

.2197224577

is this one right?

its in the interval