How do you calculate the energy delivered by a capacitor

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SUMMARY

The energy delivered by a capacitor can be calculated using the formula W = 1/2 CV², where W represents the work done, C is the capacitance, and V is the voltage. In this discussion, a capacitor with a capacitance of 10μF charged to a voltage of 20V stores an energy of 2 joules. The charge stored in the capacitor is calculated as Q = CV, resulting in a charge of 2 x 10⁻⁴ coulombs. The energy delivered by the supply is directly related to the charge and voltage, expressed as QV.

PREREQUISITES
  • Understanding of capacitor fundamentals, including capacitance and voltage.
  • Familiarity with the energy storage formula W = 1/2 CV².
  • Basic knowledge of electrical charge and its relationship with voltage.
  • Concept of conservative fields in electrical circuits.
NEXT STEPS
  • Study the derivation and applications of the energy formula W = 1/2 CV².
  • Learn about the behavior of capacitors in series and parallel circuits.
  • Explore the concept of energy conservation in electrical systems.
  • Investigate the effects of resistance in capacitor charging and discharging processes.
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Electrical engineering students, hobbyists working with capacitors, and professionals involved in circuit design and analysis will benefit from this discussion.

sefsybabe
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Homework Statement



a capacitor of capacitance 10μF is fully charged to form a 20v d.c supply
1) calculate the charge stored by the capacitor
2) calculate the energy delivered by the 20v supply

Homework Equations



1/2 cv2

The Attempt at a Solution



1) q =cv
Q= 2x10-4
i don't know how to solve the second one pls
 
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You wrote ## \frac{1}{2}C V^2 ## without an equal sign, check in your notes what's that equal to.
That equation relates C, V with something that may be interesting for you
 
sorry the equation is
W=1/2 CV2
where W=work done
 
Assumineg a stiff power supply with very low source resistance and a very large filter capacitor on the output, the energy that goes to charge the cap is QV, where Q=CV is the charge that rises through the supply through a fixed V=20volts during the near-instantaneous charging.

This energy expression QV=CV**2 is based on the definition of charge, voltage, and capacitance.

Of course, the final energy that's stored on the C=10uF capacitor is 0.5CV**2, the remainder of the charging energy having gone to series resistance, radiation, and ?
 
sefsybabe said:
W=1/2 CV2
where W=work done

work is energy
 
so is it power I am going to solve for??
 
Treat yourself to a nice schematic diagram, with the fixed-voltage supply in series with a switch and the cap.

Since you are assuming a stiff supply, all the charge is lifted through the supply at a constant voltage, so it's [(joules/coulomb)*coulomb] to get energy. Am an EE here, so most all my charge is positive and flows out of the supply into the cap.

You do not need to think about power, just energy.

Not sure if I can invoke the fact that you have a conservative field here so that the work done on a charge moving from the negative supply terminal, through the supply, to the positive supply terminal only depends on the (constant) potential difference.

Anyway, I believe you can make this a simple problem by saying the energy delivered by the supply is QV.
 
thank you
 

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