MHB How Do You Calculate the Entry Velocity of a Ball into a Basketball Hoop?

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To calculate the entry velocity of a ball into a basketball hoop, the initial conditions include a starting velocity of 7.67 m/s, a maximum height of 4 m, and the hoop height at 3 m, with the ball starting 2.1 m above the ground. The expected entry velocity is -6.42 m/s at an angle of -43.6 degrees. The user initially struggled with the equation v^2=vo^2+2a(delta x) but eventually found a solution. The discussion highlights the importance of understanding projectile motion and the correct application of kinematic equations. The problem was ultimately resolved, confirming the user's successful calculation.
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I am trying to find the velocity at which a ball enters a basketball hoop. The answer should be -6.42m/s at an angle of -43.6 degrees, but idk how to get that.

The ball starts at a velocity of 7.67m/s and reaches a max height of 4m. The hoop is 3m high, and the ball starts 2.1m above the ground. Can anyone please help.

I tried doing v^2=vo^2+2a(delta x) but I didn't get the right answer...help please!
 
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Hi Mango12,

I noticed you have the [SOLVED] tag in your title, but just to make sure, have you solved this problem entirely? Or did you figure out how to do it?
 
Euge said:
Hi Mango12,

I noticed you have the [SOLVED] tag in your title, but just to make sure, have you solved this problem entirely? Or did you figure out how to do it?

I figured out how to do it. But thank you for checking!
 
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