How Do You Calculate the Equivalent Capacitance in a Complex Circuit?

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SUMMARY

The discussion focuses on calculating the equivalent capacitance of a complex circuit involving capacitors C1 (23 µF), C2 (4.00 µF), C3 (12.0 µF), and C4 (9.00 µF) with a voltage of 12.0V. The user initially combines capacitors C1 and C3 in series, resulting in C13 = 8 µF. However, the user incorrectly assumes that C13, C2, and C4 are in parallel, leading to confusion. The correct approach is to recognize that only C13 and C2 are in parallel, which ultimately leads to the correct equivalent capacitance of 5.14 µF.

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  • Basic knowledge of capacitance and its units (microfarads)
  • Familiarity with circuit diagrams and notation
  • Ability to perform algebraic calculations involving fractions
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Homework Statement



In the diagram V = 12.0V, C1 = 23 uF, C2 = 4.00 uF, C3 = 12.0 uF and C4 = 9.00uF. Calculate the equivalent capacitance of the system.

http://img403.imageshack.us/img403/6346/eqam8.jpg

Homework Equations



Just combinding capacitors in parallel and in series.

The Attempt at a Solution



This question is giving me a headache when it should be simple. I must be overlooking something stupid, and hopefully someone will please lead me in the right direction.

I start by taking capacitors C1 and C3, which are in series, and combine them :
1/C13 = 1/24 + 1/12
1/C13 = 3/24
C13 = 8

Doesn't that leave C13, C2, and C4 in parallel? (this is where I'm getting sidetracked i think. the middle one is throwing me for a bit of a loop). In parallel, that would just be 8+4+9 = 21 uF, which is not the answer. The answer should be 5.14 uF.

I'd appreciate any pointers.
 
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Doesn't that leave C13, C2, and C4 in parallel?

No, only C13 and C2 are in parallel for the next step.
 

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