How Do You Calculate the Magnitude of the Sum of Two Vectors?

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Homework Help Overview

The problem involves calculating the magnitude of the sum of two vectors, \(\vec{A}\) and \(\vec{B}\), given their magnitudes and the angle between them. The context is rooted in vector addition and trigonometry.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply trigonometric relationships to find the components of the vectors but expresses confusion about the calculations. Some participants clarify the relationships between the components and suggest recalculating them. Others question the assumptions made about the components and the application of the vector addition formula.

Discussion Status

Participants are actively engaging with the problem, providing clarifications and corrections regarding the calculations of vector components. There is a recognition of progress, but the original poster continues to seek further clarification on the correct application of the formulas.

Contextual Notes

The discussion highlights potential misunderstandings in the setup of the problem and the calculations involved. The original poster mentions that similar problems have been challenging, indicating a broader context of learning difficulties.

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Homework Statement


Vector [tex]\vec{A}[/tex] has magnitude 3.6 units; vector[tex]\vec{B}[/tex] has magnitude 5.9 units. The angle between A and B is 45°. What is the magnitude of [tex]\vec{A}[/tex] + [tex]\vec{B}[/tex]?

Homework Equations


[tex]\Delta[/tex]V= [tex]\sqrt{V^2x +V^2y}[/tex]
"SohCahToa"


The Attempt at a Solution



I am really struggling with this for some reason. I know its just a SAS triangle.

Sin(45)=x/5.9 = opposite angle (y component, no?) =4.1719.

I tried using sqrt(4.1719^2 + 3.6^2)
where 3.6 is the x component and 4.1719 is the y component
=5.510

But, this is not correct. Basically all of my webassign problems are similar to this type, more or less complicated. Could you please point me in the right direction?


Thank you so very much for your time!
Edit: I searched but was unable to find a thread that helped. If you know of one, that would be appreciated also
 
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WPCareyDevil said:
Sin(45)=x/5.9 = opposite angle (y component, no?) =4.1719.

Mathematically, that statement is nonsense.
What you mean is, if x is the y-component of B, then
sin(45) = x / 5.9
so
x = 5.9 sin(45) = 4.1719
Let's call it By instead.

Similarly, what is the x-component Bx of B?

Then do the vector addition:
(A + B) = [ Ax + Bx, Ay + By ]
and then calculate the magnitude using the formula you gave.
 
Thank you for the reply!
Ok, I now understand that I need to calculate the x and y components of each vector.

By=4.1719
Bx=[sin(45)=3.6/x]=2.5456

Ay=[sin(45)=x/3.6]=2.5456
A=[cos(45)=x/3.6]=2.5456

Therefore A=5.09117, B=6.7175

However, when I plug this into the equation I get an incorrect answer (8.4288).Can you make it a little more clear? Thank you so much for the help.
 
Ok, making progress here.I split each of the two vectors up as right triangles with HypA=3.6, HypB=5.9

Ax will =Ay
and Bx will = By, because they are 45/45/90 triangles.

Ay+Ax=5.0912
By+Bx=8.3486

But those two numbers do not yield the correct answer in the formula either (9.774473).

What am I doing wrong? I have gotten other answers on my homework correct.

Do I need to use the formula twice? Ie (ax, ay), and then (bx, by) then add? Just thinking out loud
 

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