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## Homework Statement

Vector A⃗ has a magnitude of 20m and makes an angle of 30∘ above the positive x axis. Vector B⃗ has a magnitude of15m and is oriented 60∘ to the left of the y axis.

Find the magnitude of A⃗ −B⃗ .

Find the direction of A⃗ −B⃗ .

## Homework Equations

sin 150 = sin 30 = 0.5

cos 150= - cos 30

Angle of direction = tan-1 (y/x)

## The Attempt at a Solution

so far

Ax [/B]= 20 cos 30 =17.3 m

**Ay**= 20 sin 30 = 10 m

**Bx**=

**15**cos 150 = -12.99 m

**By**=15 sin 150 = 7.5 m

**add Ax+Bx=**4.31

**Ay+By=**17.5

sqrt of [(4.31)^2+(17.5)^2]= 18.0

**but i dont know where to go from here ?**

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