How Do You Calculate the Mass of a Block from a Bullet and Spring Collision?

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To calculate the mass of the wooden block after a bullet embeds itself in it, apply the conservation of momentum and energy principles. The bullet's initial momentum is transferred to the block-spring system, where the spring's compression can be used to find the block's mass. Given the spring constant of 99 N/m and a maximum compression of 1.2 cm, the energy stored in the spring can be equated to the kinetic energy of the bullet-block system. The calculations indicate that the block's mass must be significantly large to account for the low velocity after the collision. Understanding these principles is essential for solving the problem accurately.
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Homework Statement


A 34g bullet traveling at 120m/s embeds itself in a wooden block on a smooth surface. The block then slides toward a spring and collides with it. The block compresses the spring (k=99N/m) a maximum of 1.2 cm. Calculate the mass of the block of wood.


Homework Equations


Not sure.
m1v1 + m2v2 = (m1 + m2)v'
Ee = .5kx2
Ek = .5mv2


The Attempt at a Solution


I'm fairly certain it's incorrect. I just don't know where.
IMG_NEW.jpg


Thanks!
 
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I see your concern with the mass of the wooden block. Your approach is correct. Consider the spring. It has a spring constant of 99N/m. This means if the spring were used as a scale a 10 kg mass would compress the spring 1 meter. A very weak spring. Since the spring compressed .012 meters your answer is reasonable; the velocity of the bullet-block system would have to be very small meaning a very large mass for the block.
 
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