How Do You Calculate the Mass of a Star Based on Planetary Data?

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Homework Help Overview

The discussion revolves around calculating the mass of a star based on planetary data, specifically using gravitational force and orbital mechanics. The original poster presents a scenario involving a planet's diameter, rotation period, orbital period, and gravitational acceleration to determine both the mass of the planet and the mass of the star it orbits.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using gravitational equations and Kepler's laws to find the mass of the star. There are attempts to clarify the correct application of formulas and the necessary parameters, such as the distance from the planet to the star and the orbital period.

Discussion Status

Participants are actively engaging with the problem, sharing calculations and questioning the accuracy of their results. Some guidance has been offered regarding the correct formulas and the relationships between the variables involved, though there is no explicit consensus on the correct approach yet.

Contextual Notes

There are mentions of potential errors in calculations and assumptions about the mass of the star relative to the planet. The discussion also highlights the need for careful handling of units and exponents in the equations used.

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Gravitational Force---Need Help Fast!

Homework Statement



You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.8*10^7 m and its rotation period to be 22.3 hours. You have previously determined that the planet orbits from its star with a period of 402 Earth days. Once on the surface you find that the acceleration due to gravity is 12.2 m/s^2.

What is the mass of the planet? in kg

What is the mass of the star? in kg

Equations:
Mass(of planet)= g*R^2/G

The Attempt at a Solution



Ok, so I calculated the mass of the planet to be 1.48*10^25 kg using the above equation. M=[(12.2m/s^2)*(9*10^6m)^2]/6.67*10^-11 Nm^2/kg^2.

Now I am stuck with how to find the mass of the star and which equation to use to get it..

Thank you
 
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It states that the planet orbits 2.2*10^11 m from its star. This would them be the distance, correct??
 
So, then I use T^2=4pi^2/GM somehow? I guess I'm not exactly sure how...
 
oops, I forget r^3 in the equation..
so:

T^2=(4pi^2/GM)r^3
 
T should = 34732800 sec
r should be 2.2*10^11 m

correct??
 
Using that I calculated the mass of the star to be 1.39 * 10^64...
but that is wrong...
so where did I go wrong??
 
I calculated it again and this time I got 1.44*10^37, but that is also wrong...

What am I doing wrong?
 
  • #10
If I rearrange the equation to find the mass of the star this is what I get:

M=[(2pir^3/2)^2]/GT

Is this right? It is what I have been using, but I can't come up with the correct answer.
 
  • #11
tibessiba said:
It states that the planet orbits 2.2*10^11 m from its star. This would them be the distance, correct??
Yes, that is a or r in Kepler's forumula relating period with distance for one mass orbiting another mass, e.g. moon around a planet or planet about a star.

In the simplest form, one may assume that the mass of the star greatly exceeds the mass of the planet.

So T^2\,=\,\frac{4{\pi^2}{a^3}}{GM}, which can be rearranged to get

M\,=\,\frac{4{\pi^2}{a^3}}{GT^2}

So substitute in the appropriate numbers

G = 6.67 x 10-11 N m2/kg2, the universal gravitational constant,

a = 2.2 x 1011 m

T = 402 d * 24 h/d * 3600 s/h = 3.47328 x 107 s

Now compare the mass of the star with the mass of the planet. The mass calculated for the star might need adjusting for the mass of the planet since M is the sum of the masses, but if M >> m(planet), the M is approximately the mass of the star.

M=[(2pir^3/2)^2]/GT
This is not correct. Be careful about moving terms and exponents. T should be squared and if one brings r^3 inside the parentheses and squares those terms, then one must use r^(3/2) within the parentheses.
 
Last edited:
  • #12
Ok... I see.

Thank you very much!
 

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