- #1
startinallover
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I'm doing a report on a set of lab data and am supposed to find the mean and mean's standard deviation
\bar{x} + \sigma_{\bar{x}}
The mean is given by
\displaystyle{ \bar{x} = \sum_{i=1}^{N} w_{i} x_{i} }
Where
\displaystyle{ w_{i} = \left( \frac{\sigma}{\sigma_{i}} \right)^2 }
and for the error (mean's standard deviation)
\displaystyle{ \sigma_{\bar{x}} = \sigma = \frac{1}{ \sqrt{ \sum_{i=1}^{N} \frac{1}{\sigma_{i}^{2} } } } }The problem is I can't quite figure it out what the σi would be, is it the standard deviation? This might sound very silly but it's been a long time I've dealt with this.
Any help is appreciated.
\bar{x} + \sigma_{\bar{x}}
The mean is given by
\displaystyle{ \bar{x} = \sum_{i=1}^{N} w_{i} x_{i} }
Where
\displaystyle{ w_{i} = \left( \frac{\sigma}{\sigma_{i}} \right)^2 }
and for the error (mean's standard deviation)
\displaystyle{ \sigma_{\bar{x}} = \sigma = \frac{1}{ \sqrt{ \sum_{i=1}^{N} \frac{1}{\sigma_{i}^{2} } } } }The problem is I can't quite figure it out what the σi would be, is it the standard deviation? This might sound very silly but it's been a long time I've dealt with this.
Any help is appreciated.