How Do You Calculate the Modulus and Argument of a Complex Number?

Click For Summary
SUMMARY

This discussion focuses on calculating the modulus and argument of a complex number, particularly using Euler's formula. The modulus of a complex number \( z = a + ib \) is defined as the length of the vector in the Argand diagram, while the argument is the angle it makes with the x-axis. The discussion highlights the transformation of \( (e^{i\theta})^2 \) into \( e^{2i\theta} \) and confirms that the real part is \( \cos(2\theta) \) and the imaginary part is \( \sin(2\theta) \) through double angle identities. Understanding these concepts is essential for manipulating complex numbers effectively.

PREREQUISITES
  • Understanding of complex numbers and their representation in the Argand diagram
  • Familiarity with Euler's formula \( e^{i\theta} = \cos(\theta) + i\sin(\theta) \)
  • Knowledge of trigonometric identities, particularly for double angles
  • Basic algebraic manipulation of exponential functions
NEXT STEPS
  • Research how to derive the modulus of a complex number \( z = a + ib \)
  • Learn about polar coordinates and their application to complex numbers
  • Study trigonometric identities for \( \cos(2\theta) \) and \( \sin(2\theta) \)
  • Explore advanced applications of Euler's formula in complex analysis
USEFUL FOR

Mathematicians, physics students, and anyone studying complex analysis or needing to perform calculations involving complex numbers.

joelstacey
Messages
2
Reaction score
0
Homework Statement
For each expression, evaluate its real part, imaginary part, modulus and argument.
1. (e^(i*theta))^2
Relevant Equations
r*e^(i*theta)= r*(cos(theta) + i*sin(theta))
(e^(i*theta))^2 = (sin(theta)+i*cos(theta))^2 = cos(theta)^2 - sin(theta)^2 + 2*i*sin(theta)*cos(theta), so the real part would be: cos(theta)^2 - sin(theta)^2, and the imaginary part would be: 2*i*sin(theta)*cos(theta). But then I don't know where to start with the modulus or the argument?
 
Physics news on Phys.org
What are the definition of the modulus and argument of a complex number?
 
Office_Shredder said:
What are the definition of the modulus and argument of a complex number?
I know the modulus is the length of the vector in an argand diagram, and the modulus is the angle it makes with the x axis, but since it is squared i don't see how it works as an argand diagram.
 
You can also write ##(e^{i\theta})^2## as ##e^{2i\theta}##, using the properties of exponents.
Rewriting the above using Euler's formula, we have ##e^{2i\theta} = \cos(2\theta) + i\sin(2\theta)##, which agrees with what you found for the real and imaginary parts (after using double angle identities).

If you have a complex number ##z = a + ib##, how do you find the modulus? From the above, the argument (arg) should be simple to find.
 
I guess a couple of things
1.) Given the real and complex parts, you could write down a new polar coordinates form. The modulus is not hard to compute this way, though I will admit the argument requires knowing some trig trickery.
2.) There's a much simpler way to do this.
## (e^{i\theta})^2 = e^{i\theta} e^{i\theta} = e^{i\theta+i\theta}##.

Note ##(e^a)^b \neq e^{ab}## in general, but when b is an integer you can do this.
 
Last edited:
joelstacey said:
...
so the real part would be: cos(theta)^2 - sin(theta)^2, and the imaginary part would be: 2*i*sin(theta)*cos(theta). But then I don't know where to start with the modulus or the argument?
Do you know the trig identities for ##\cos(2\theta)## and ##\sin(2\theta) ## ?
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
9
Views
4K