How Do You Calculate the Modulus and Argument of a Complex Number?

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Homework Help Overview

The discussion revolves around calculating the modulus and argument of a complex number, particularly focusing on expressions involving Euler's formula and trigonometric identities.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between the exponential form of complex numbers and their representation in polar coordinates. Questions arise about the definitions of modulus and argument, as well as how to apply trigonometric identities in this context.

Discussion Status

Some participants have provided insights into rewriting complex expressions and have begun discussing the implications of these transformations for finding the modulus and argument. There is an ongoing exploration of definitions and relationships without a clear consensus on the next steps.

Contextual Notes

There is some confusion regarding the application of trigonometric identities and how they relate to the squared terms in the context of the Argand diagram. Participants are also considering the implications of the properties of exponents in their calculations.

joelstacey
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Homework Statement
For each expression, evaluate its real part, imaginary part, modulus and argument.
1. (e^(i*theta))^2
Relevant Equations
r*e^(i*theta)= r*(cos(theta) + i*sin(theta))
(e^(i*theta))^2 = (sin(theta)+i*cos(theta))^2 = cos(theta)^2 - sin(theta)^2 + 2*i*sin(theta)*cos(theta), so the real part would be: cos(theta)^2 - sin(theta)^2, and the imaginary part would be: 2*i*sin(theta)*cos(theta). But then I don't know where to start with the modulus or the argument?
 
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What are the definition of the modulus and argument of a complex number?
 
Office_Shredder said:
What are the definition of the modulus and argument of a complex number?
I know the modulus is the length of the vector in an argand diagram, and the modulus is the angle it makes with the x axis, but since it is squared i don't see how it works as an argand diagram.
 
You can also write ##(e^{i\theta})^2## as ##e^{2i\theta}##, using the properties of exponents.
Rewriting the above using Euler's formula, we have ##e^{2i\theta} = \cos(2\theta) + i\sin(2\theta)##, which agrees with what you found for the real and imaginary parts (after using double angle identities).

If you have a complex number ##z = a + ib##, how do you find the modulus? From the above, the argument (arg) should be simple to find.
 
I guess a couple of things
1.) Given the real and complex parts, you could write down a new polar coordinates form. The modulus is not hard to compute this way, though I will admit the argument requires knowing some trig trickery.
2.) There's a much simpler way to do this.
## (e^{i\theta})^2 = e^{i\theta} e^{i\theta} = e^{i\theta+i\theta}##.

Note ##(e^a)^b \neq e^{ab}## in general, but when b is an integer you can do this.
 
Last edited:
joelstacey said:
...
so the real part would be: cos(theta)^2 - sin(theta)^2, and the imaginary part would be: 2*i*sin(theta)*cos(theta). But then I don't know where to start with the modulus or the argument?
Do you know the trig identities for ##\cos(2\theta)## and ##\sin(2\theta) ## ?
 

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