How Do You Calculate the Moment of Inertia for a Uniform Solid Block?

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SUMMARY

The moment of inertia for a uniform solid block with mass 0.172 kg and dimensions 3.5 cm x 8.4 cm x 1.4 cm can be calculated using the formula for rotational inertia, which is the integral of r² dm. In this case, r² is defined as a² + b², where a and b are the edge lengths. To substitute for dm, one must use the density of the block multiplied by the differential volume elements, specifically dm = density times dxdydz, or for two dimensions, dm = hdxdy.

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  • Understanding of moment of inertia concepts
  • Familiarity with integral calculus
  • Knowledge of density and its application in physics
  • Basic geometry of rectangular solids
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  • Learn about the application of density in calculating mass
  • Explore integral calculus techniques for multi-variable functions
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demonelite123
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a uniform solid block has mass 0.172 kg and edge lengths a=3.5cm, b=8.4cm, and c=1.4cm (c is the height of the rectangular solid).Calculate its rotational inertia about an axis through one corner and perpendicular to the large faces.

i know the formula is integral of r^2 dm, but i have no idea what to do here. i have r^2 = a^2 + b^2. but i don't know how what to substitute for dm.
 
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Hi demonelite123! :smile:

(try using the X2 tag just above the Reply box :wink:)
demonelite123 said:
i know the formula is integral of r^2 dm, but i have no idea what to do here. i have r^2 = a^2 + b^2. but i don't know how what to substitute for dm.

If r2 = x2 + y2, then dm = density times dxdydz (or, if you're only integrating over x and y, then dm = hdxdy). :smile:
 

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