How Do You Calculate the Percent Change in Momentum for a Lorry?

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SUMMARY

The discussion focuses on calculating the percentage change in momentum for a lorry transitioning from a loaded state to an unloaded state while maintaining a constant velocity of 13.41 m/s. The loaded lorry has a mass of 3100 kg, and the unloaded lorry weighs 2300 kg. The correct calculation shows a 25.8% decrease in momentum, derived from the formula: percentage change = (change / momentum_full) * 100%, where change is calculated as momentum_full - momentum_unloaded.

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spritchs
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% Change in Momentum

1. I do not understand how to do this question as part of my revision. can anyone help? ''Calculate the % change in the momentum of the lorry from loaded to unloaded whilst traveling at a constant velocity of 13.41m/s''



2. Momentum = mass x velocity? Loaded lorry weighs 3100kg unloaded weighs 2300kgs.
 
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would change be 25.8% decrease in momentum from loaded to unloaded?
 
spritchs said:
would change be 25.8% decrease in momentum from loaded to unloaded?

Yup, that looks correct to me.

[In future, please show your work, as it is easier for someone to check your work than to do it themselves!]
 
Last edited:
change = momentum_full - momentum unloaded = m1v - m2v = v(m1-m2)

percentage change = (change / momentum_full) * 100%
 
Last edited:
yeah, i know, i corrected it right after i'd posted it.
 
dobry_den said:
yeah, i know, i corrected it right after i'd posted it.

Which is why I deleted my last post :smile:
 

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