How Do You Calculate the Probability of Drawing Two Red Balls from an Urn?

  • Context: High School 
  • Thread starter Thread starter blob84
  • Start date Start date
  • Tags Tags
    Balls Probability
Click For Summary
SUMMARY

The probability of drawing two red balls from an urn containing 3 red balls and 2 white balls without replacement is calculated using the formula \(\frac{\binom{3}{2}}{\binom{5}{2}}\). The sample space consists of all distinct combinations of drawing two balls from the total of five, represented as 5C2. The events can be defined as R_1 (the first ball is red) and R_2 (the second ball is red), which are not disjoint. The total number of favorable outcomes for drawing two red balls is represented by 3C2.

PREREQUISITES
  • Understanding of combinatorial mathematics, specifically binomial coefficients
  • Knowledge of probability theory and events
  • Familiarity with the concept of sample space in probability
  • Basic skills in mathematical notation and set theory
NEXT STEPS
  • Study combinatorial techniques using binomial coefficients
  • Learn about probability distributions and their applications
  • Explore advanced topics in set theory related to probability
  • Practice problems involving drawing objects without replacement
USEFUL FOR

Students in mathematics, educators teaching probability, and anyone interested in combinatorial problems and their applications in real-world scenarios.

blob84
Messages
25
Reaction score
0
Hi, if in an urn there are 3 red balls and 2 white balls and we draw 2 balls from the urn without replacement.
If we assume that at each ball in the urn is equally likely to be chosen, what is the probability that both balls are red?

I know the solution is \frac{\binom{3}{2}}{\binom{5}{2}}, but i want to show the elements of the sample space, for example are they the elements: r_1, r_2, r_3, w_1, w_2?
If i split the events in two disjoint events as R_1={the first ball is red} and R_{the second ball is red} what are the elements of these sets?
 
Last edited:
Physics news on Phys.org
R_1 and R_2 are not disjoint.
 
The sample space in this question contains all distinct ways of choosing two of the five balls, with 5C2 elements. Your event (in which both balls are red) has 3C2 elements, the number of distinct ways of choosing two of the three red balls.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K