How Do You Calculate the Sliding Distance with Friction and Initial Forces?

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Homework Help Overview

The discussion revolves around calculating the sliding distance of a person on a frictional surface after being pushed, with a focus on the forces involved and the work-energy principle. The subject area includes concepts of friction, kinetic energy, and work done in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between work done by a pushing force and the work done against friction. There are attempts to calculate kinetic energy and total work done, with some participants expressing confusion about how to integrate these concepts.

Discussion Status

The discussion is active, with participants exploring different aspects of the problem. Some have offered hints regarding the calculations needed to determine total work done, while others are working through the implications of friction on the sliding distance.

Contextual Notes

Participants are operating under the assumption that the coefficient of friction remains constant and are considering the effects of both the push and friction during the sliding motion. There is a hint of uncertainty regarding the correct application of work-energy principles in this context.

junior78
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I got the first part done but I am getting confused with B because I know the work done by the push - force by my friction should equal the force done by my cousins force by friction..I know I am right there I just can't put the equation together because I am getting stuck any help Please

Suppose that the coefficient of friction between your feet and the floor, while wearing socks, is 0.250. Knowing this, you decide to get a running start and then slide across the floor.

a) If your speed is 3.00 m/s when you start to slide, what distance d will you slide before stopping?

F*d = 1/2mv^2
.250m(9.8 )*d = 1/2m(3)^2
d = 1/2(3)^2 / .25(9.8 )
d = 1.8367 m

b) Now, suppose that your young cousin sees you sliding and takes off her shoes so that she can slide as well (assume her socks have the same coefficient of friction as yours). Instead of getting a running start, she asks you to give her a push. So, you push her with a force of 125 N over a distance of 1.00 m. If her mass is 20.0 kg, what distance d does she slide (i.e., how far does she move after the push ends)? Remember that the friction force is acting anytime that she is moving.
 
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Find her kinetic energy after the push. Hint: What's the total work done on her?
 
ok let me see so her kenetic energy afte rthe push will take the variables as t
m=20kg
v=9.80
giving a energy of 960.4N
TOTAL WORK DONE = is the work of 125N times the coefficient plus the 1.00m of distance now what??
 
To find the total work done during the push, consider the work done by the 125 N force and the (negative) work done by friction over the 1 m distance of the push.
 
OHHH ok I got it finally ...appreciate all your help
 

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