How Do You Calculate the Solubility of Sodium Sulfite?

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The solubility of sodium sulfite (Na2SO3) at 20 degrees Celsius is 27 g per 100 g of water, leading to a mass percent concentration of 21% for a saturated solution. To calculate the grams of sodium sulfite heptahydrate (Na2SO3·7H2O) soluble in 50 g of water, one must consider the mass percent concentration derived from the first calculation. The solution involves using the mass percent formula and accounting for the additional mass from the heptahydrate form.

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I have a large exam tomorrow in chemistry and know how to do most problems on my practice test except these two

If the solubility of sodium sulfite (Na2SO3) is 27(g/100g water) at 20 degrees celsius, what is the mass percent concentration of the saturated solution of Na2SO3 at 20 degrees celsius?

How many grams of Na2SO3 * 7H2O is soluble in 50g water at 20 degrees celsius?



the answer to the first question is 21 and the 2nd answer is 37 but for the life of me I can't figure out how they got these answers.
 
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For the first one, mass percent of Na2SO3 = mass of Na2SO3 / total mass of solution. If you assume you have a saturated solution with 27 g Na2SO3, what's the total mass of the solution? Then you'll need this result for the next one.

The second one is a little tricky since you're working with the added water in Na2SO3·7H2O. Use the equation for finding the mass percent of Na2SO3 while using x for the moles of Na2SO3 and Na2SO3·7H2O; this mass percent of Na2SO3 must be equal to the mass percent you got for the first problem.
 

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