How Do You Calculate the Solubility Product for Copper(I) Sulfide?

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SUMMARY

The solubility product constant (Ksp) for copper(I) sulfide (Cu2S) is calculated to be 2.5 × 10-48. This value is derived from the equilibrium expression Ksp = [Cu+]2[S2-], using the solubility of Cu2S, which is 8.5 × 10-17 M. The concentration of Cu+ is twice that of Cu2S due to the dissociation of two copper ions per formula unit. The calculations confirm the accuracy of the Ksp value.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with solubility product constants (Ksp)
  • Knowledge of dissociation reactions in ionic compounds
  • Basic algebra for manipulating scientific notation
NEXT STEPS
  • Study the principles of chemical equilibrium in detail
  • Learn about the calculation of Ksp for different ionic compounds
  • Explore the effects of temperature on solubility and Ksp
  • Investigate applications of Ksp in predicting precipitation reactions
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Homework Statement



What is the solubility product for copper(I) sulfide, Cu2S, given that the solubility of Cu2S is 8.5 × 10-17 M?

Homework Equations



Cu_{2}S \leftrightarrow 2Cu^{+} + S^{2-}

The Attempt at a Solution



Set up the equilibrium constant expression:
K_{sp} = [Cu^{+}]^{2}[S^{2-}]

Replaced values:
K_{sp} = (2*8.5 × 10^{-17})^{2}(8.5 × 10^{-17})
K_{sp} = 2.5 * 10^{-48}

A double-check on this would be wonderful please.
 
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