How Do You Calculate the Square Root of a Polynomial?

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To calculate the square root of a polynomial, one must find a polynomial p(x) such that [p(x)]² equals the given polynomial q(x). For the polynomial 4x^4 + 8x^3 + 8x^2 + 4x + 1, it is not possible to find such a p(x) because q must have roots with even multiplicities, which this polynomial does not possess. Attempting to express p as ax² + bx + c and squaring it leads to a system of equations that has no solution. Therefore, finding the square root of this specific polynomial is not feasible. Understanding the conditions for polynomial roots is crucial in these calculations.
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does anyone know any specific method to find the square root of a polynomial like : 4x4 + 8x3 + 8x2 + 4x+ 1 ??
thanks in advance!
 
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You want to find a polynomial p(x) such that [p(x)]2 = q(x)?
If this is it, it is not possible, for a general q, to find p. q must have roots with even multiplicities. This is not the case in your example. Try putting p = ax2+bx+c, square it, and equate coefficients with q. You'll find a system of equations with no solution.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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