How Do You Calculate the Velocity of the Center of Mass?

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SUMMARY

The velocity of the center of mass (vcm) for two blocks moving along the x-axis can be calculated using the formula vcm = [(m1)(v1x) + (m2)(v2x)] / (m1 + m2). This equation expresses the x component of the center of mass velocity in terms of the masses (m1, m2) and their respective velocities (v1x, v2x). The discussion confirms the validity of this formula and addresses a scenario where only velocities are known, indicating a need for further clarification on handling such cases.

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  • Understanding of basic physics concepts, specifically center of mass.
  • Familiarity with calculus, particularly derivatives.
  • Knowledge of vector components in motion.
  • Ability to manipulate algebraic equations involving mass and velocity.
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  • Study the principles of center of mass in multi-body systems.
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akaur
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1. Recall that the blocks can only move along the x axis. The x components of their velocities at a certain moment are v1x and v2x. Find the x component of the velocity of the center of mass (vcm)x at that moment. Express your answer in terms of m1, m2, v1x, and v2x



2. Keep in mind that, in general: v= dx/dt.



3. its the derivative of xcm = (m1x1 + m2x2) / (m1 + m2)...so does vcm= [(m1)(v1x) + (m2)(v2x)] / (m1 + m2) ?
 
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akaur said:
1. Recall that the blocks can only move along the x axis. The x components of their velocities at a certain moment are v1x and v2x. Find the x component of the velocity of the center of mass (vcm)x at that moment. Express your answer in terms of m1, m2, v1x, and v2x



2. Keep in mind that, in general: v= dx/dt.



3. its the derivative of xcm = (m1x1 + m2x2) / (m1 + m2)...so does vcm= [(m1)(v1x) + (m2)(v2x)] / (m1 + m2) ?


yes. looks right to me.
 
what if you don't have the masses, cause I am stuck on one question that has just 2 velocities going in the positive x direction
 

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