- #1
leunglik
- 4
- 0
A particle moves in the xy-plane so that the position of the particle is given by
x(t)=5t+3sint , y(t)=(8-t)(1-cost)
Find the velocity vector at the time when the particle's horizontal position is x=25
answer is (7.008, -2.228)
*the x=25, i think the trick is somehow get the t with that..
x(t)=5t+3sint , y(t)=(8-t)(1-cost)
Find the velocity vector at the time when the particle's horizontal position is x=25
answer is (7.008, -2.228)
*the x=25, i think the trick is somehow get the t with that..