How Do You Calculate the Volume Between a Cone and a Sphere?

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To calculate the volume between a cone defined by Φ = π/3 and a sphere given by ρ = 4cosΦ, the bounds for ρ should indeed start from 0, as it represents the distance from the origin. The confusion arises from interpreting the region above the cone and below the sphere; the volume is not limited to just the top of the cone. The correct bounds for the triple integral are 0 ≤ ρ ≤ 4cosΦ, with Φ ranging from 0 to π/3. Understanding the geometric representation is crucial, as different textbooks may define spherical coordinates differently. The discussion emphasizes the importance of correctly visualizing the shapes involved to accurately set up the integral.
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Homework Statement



Find volume of the solid that lies above the cone Φ = π/3 and below the sphere ρ = 4cosΦ

Homework Equations

The Attempt at a Solution



Obviously this is a triple integral. My book tells me that 0 ≤ρ≤ 4cosΦ

but this makes no sense to me.

From the problem, it lies ABOVE the cone Φ = π/3 and below the sphere ρ = 4cosΦ, so wouldn't that imply that ρ is not starting at 0?

What I did was solved ρ = 4cosΦ

arccos(ρ/4) = Φ and set it = to pi/3

arccos(ρ/4) = π/3

ρ/4 = cosπ/3

ρ = 4 * (1/2) = 2

so wouldn't 2≤ρ≤4cosΦ be the bounds? I don't understand how the lower bound can start at 0 when its asking for what's above the cone and below the sphere..
 
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Rijad Hadzic said:
wouldnt that imply that ρ is not starting at 0?
No. Also, please define your variables.

I suggest you draw an image of what things look like.
 
Orodruin said:
No. Also, please define your variables.

I suggest you draw an image of what things look like.

ρ is the distance to the point from the origin
Φ is the angle from the z axis to the point. 0≤Φ≤pi
θ is the angle to the point from the projection in the xy plane.

I did draw an image, it looks like an icecream cone basically. The part I want is the icecream on the top of the cone. I still don't understand why ρ is 0..
 
Hmm I think I may be graphing it wrong. Maybe I have no clue how to graph ρ = 4cosΦ..
 
Rijad Hadzic said:
ρ is the distance to the point from the origin
Φ is the angle from the z axis to the point. 0≤Φ≤pi
θ is the angle to the point from the projection in the xy plane.
Different textbooks treat spherical coordinates in different ways, particularly the ##\theta## and ##\phi## coordinates. According to this wikipedia article (https://en.wikipedia.org/wiki/Spherical_coordinate_system), physics books consider ##\phi## to be the angle in the "x-y" plane, while math textbooks consider ##\phi## to be measured from the positive z-axis.
 
Rijad Hadzic said:
The part I want is the icecream on the top of the cone.
No, this is not correct. The "cone" that the problem talks about is the mantle surface of the cone. If it was just the top that was intended, the problem would talk about a plane, not about a cone.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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