How Do You Calculate the Volume of a Rotated Solid?

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SUMMARY

The volume of the solid obtained by rotating the region bounded by the curves \(x = 2\sqrt{y}\), \(x = 0\), and \(y = 9\) can be calculated by first determining the points of intersection. The intersection occurs at \(y = 0\) (point (0,0)) and \(y = 9\) (point (6,9)). To find the volume, one must sketch the region and apply the disk or washer method for integration. This approach ensures accurate calculations for the volume of the rotated solid.

PREREQUISITES
  • Understanding of the disk and washer methods for volume calculation
  • Knowledge of graphing functions and identifying points of intersection
  • Familiarity with basic calculus concepts, particularly integration
  • Ability to manipulate equations involving square roots
NEXT STEPS
  • Learn the disk method for calculating volumes of solids of revolution
  • Study the washer method for cases involving gaps between curves
  • Practice finding points of intersection for various functions
  • Explore integration techniques for calculating area and volume
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Students studying calculus, educators teaching volume calculations, and anyone interested in solid geometry and integration techniques.

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Question: Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the region, the solid, and a typical disk or washer.

$$x = 2\sqrt{y}, x = 0, y = 9$$

So I know what the graph looks like. But how do i find the points of intersection? wouldn't i just set them equal to each other? so like $$2\sqrt{y} = 9$$ and solve? but how do I solve this equation properly?
 
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shamieh said:
Question: Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the region, the solid, and a typical disk or washer.

$$x = 2\sqrt{y}, x = 0, y = 9$$

So I know what the graph looks like. But how do i find the points of intersection? wouldn't i just set them equal to each other? so like $$2\sqrt{y} = 9$$ and solve? but how do I solve this equation properly?

You have the equation $$x=2\sqrt{y}$$ and you have the equation $x=0$. Just plug the value of $x=0$ in the equation of the curve. So we have $2\sqrt{y}=0$ and hence by squaring we have $4y=0$ or $y=0$. Hence the curve $x=2\sqrt{y}$ intersects the y-axis at the point $(0,0)$. Similariy find the point of intersection of the two cruves $x=2\sqrt{y}$ and $y=9$.
 
oh i see! Thanks! so then by setting y = 0 I get 9, then i plug in 9 back to the function and get 2*3 =6, so it intersects at (6,9) ?
 
shamieh said:
oh i see! Thanks! so then by setting y = 0 I get 9

Why setting the value of $y=0$ ?

, then i plug in 9 back to the function and get 2*3 =6, so it intersects at (6,9) ?

Correct !
 
shamieh said:
Question: Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the region, the solid, and a typical disk or washer.

$$x = 2\sqrt{y}, x = 0, y = 9$$

So I know what the graph looks like. But how do i find the points of intersection? wouldn't i just set them equal to each other? so like $$2\sqrt{y} = 9$$ and solve? but how do I solve this equation properly?

When doing any area or volume of region questions, the first step should ALWAYS be to do a sketch of the region. Then you can at least get an idea of where the intersections are and this can give you an idea on how to refine them.
 

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