How Do You Calculate the Wavelength of Particle Motion in Parametric Equations?

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SUMMARY

The discussion centers on calculating the wavelength of particle motion defined by the parametric equations \(\dot{x}(t) = A (1 - \cos{\Omega t})\) and \(\dot{y}(t) = A \sin{\Omega t}\). The wavelength is proposed as \(\lambda = \Omega v\), where \(v = \sqrt{\dot{x}^2 + \dot{y}^2}\). However, the validity of this formula is questioned due to the non-invariance of wavelength over time and the distinction between angular velocity \(\Omega\) and period \(T\). The confusion arises from the interpretation of \(\Omega\) as a period rather than an angular frequency.

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Logarythmic
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I have two parametric equations for the speed of a particle in a plane:

\dot{x}(t) = A \left( 1 - cos{\Omega t} \right)
\dot{y}(t) = A sin{\Omega t}

The period is equal to \Omega. How do I find the wavelength of the motion?


The wavelength is just \lambda = \Omega v, where v = \sqrt{\dot{x}^2 + \dot{y}^2} is the speed, right? But then the wavelength is not time invariant. Could my answer

\lambda = \Omega A \left( 2 - 2cos{\Omega t} \right)^{1/2}

really be correct?
 
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Here omega is not the period, but the angular velocity = 2pi/T where T is the period.
 
I thought about that too, but it's stated in the problem that the motion is periodic with period \Omega. Anyway, my question still remains.
 
Logarythmic said:
I thought about that too, but it's stated in the problem that the motion is periodic with period \Omega. Anyway, my question still remains.
Is this problem in a textbook, or was it given by a professor or teacher?

\Omega as a period would seem to be incorrect since normally the arguments of sine and cosine are dimensionless, which is consistent with rl.bhat's comment.
 

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