How Do You Calculate Time Difference in Different Inertial Systems?

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SUMMARY

The discussion focuses on calculating the time difference between two events in different inertial systems, specifically using the spacetime interval formula, s² = x² + y² + z² - (ct)². The initial calculation incorrectly used 9000 km as 9 m, leading to an erroneous time difference of 2.108 x 10^-8 seconds. The correct approach involves ensuring proper unit conversion and algebraic manipulation, particularly dividing by the speed of light squared (c²) before taking the square root.

PREREQUISITES
  • Understanding of spacetime intervals in special relativity
  • Familiarity with the speed of light (c) and its significance in physics
  • Basic algebra skills for manipulating equations
  • Knowledge of unit conversion, particularly between kilometers and meters
NEXT STEPS
  • Review the concept of spacetime intervals in special relativity
  • Learn about the Lorentz transformation equations
  • Study unit conversion techniques, especially in physics contexts
  • Practice solving problems involving time dilation and simultaneity in different inertial frames
USEFUL FOR

Students studying physics, particularly those focusing on special relativity, as well as educators seeking to clarify concepts related to inertial frames and spacetime intervals.

jimmypoopins
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Homework Statement


Two events occur in an inertial system at the same time, but 9000 km apart. However in another inertial system these two events are observed to be 11000 km apart.

What is the time difference between the two events in this second inertial system?


Homework Equations


s^2=x^2+y^2+z^2-(ct)^2


The Attempt at a Solution


since the spacetime interval is invariant in any inertial frame, s^2 can equal s'^2
for the first inertial system i got s^2=9m^2
putting it into the second equation i got
9m^2=11m^2-(ct)^2
subtracting 11m^2, dividing by -c, and taking the square root, i am left with 2.108*10^-8sec, which seems like it could be a reasonable answer, but it is not correct.

can anyone tell me what i am doing wrong and lead me in the right direction please?
 
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jimmypoopins said:

Homework Statement


Two events occur in an inertial system at the same time, but 9000 km apart. However in another inertial system these two events are observed to be 11000 km apart.

What is the time difference between the two events in this second inertial system?


Homework Equations


s^2=x^2+y^2+z^2-(ct)^2


The Attempt at a Solution


since the spacetime interval is invariant in any inertial frame, s^2 can equal s'^2
for the first inertial system i got s^2=9m^2
putting it into the second equation i got
9m^2=11m^2-(ct)^2
subtracting 11m^2, dividing by -c, and taking the square root, i am left with 2.108*10^-8sec, which seems like it could be a reasonable answer, but it is not correct.

can anyone tell me what i am doing wrong and lead me in the right direction please?

You have the right idea, it just seems that you are making some algebra mistake. First, it is 9000 km apart so [itex]9 \times 10^6 m[/itex]. Second, when solving for the time interval in the other frame, you must divide by the square of c before taking the square root.
 
ah you are right, thank you. for some reason when i saw 4000km i assumed that i had to divide by 1000 to get it in meters. i don't know why, a stupid mistake on my part.
 

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