How Do You Calculate Transient Current with Given Circuit Components?

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SUMMARY

The discussion centers on calculating the transient current in a circuit with a 12 V battery, a 1 µF capacitor, a 1 kΩ resistor, and a 0.2 H inductor. The primary equation used is i = Cdv/dt. Participants unanimously agree that connecting a battery directly to a capacitor without any resistance is illogical, as the transient current would be limited solely by the equivalent series resistance (ESR) of the capacitor. Clarification of the circuit diagram is necessary for accurate analysis.

PREREQUISITES
  • Understanding of transient analysis in electrical circuits
  • Familiarity with capacitor and inductor behavior
  • Knowledge of equivalent series resistance (ESR)
  • Proficiency in using differential equations for circuit analysis
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  • Study the impact of ESR on capacitor charging in circuits
  • Learn about transient response in RLC circuits
  • Explore circuit simulation tools like LTspice for transient analysis
  • Review the principles of Kirchhoff's laws in circuit design
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Electrical engineering students, circuit designers, and anyone involved in analyzing transient responses in electrical circuits will benefit from this discussion.

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Homework Statement



Battery Voltage = 12 V, C = 1uF, R = 1Kohm, L = 0.2H. Find Transient Current. See Fig for more details.

2djnbl2.jpg


Homework Equations



i = Cdv/dt.


The Attempt at a Solution


(I think the problem doesn't make sense)
 
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mym786 said:

Homework Statement



Battery Voltage = 12 V, C = 1uF, R = 1Kohm, L = 0.2H. Find Transient Current. See Fig for more details.

2djnbl2.jpg


Homework Equations



i = Cdv/dt.


The Attempt at a Solution


(I think the problem doesn't make sense)

As drawn, the problem does not make sense. You would not connect a battery directly to a capacitor. The transient current would only be limited by the ESR of the cap.

Can you scan the actual question for us?
 
The original diagram is drawn in pencil. The scanned copy is not so clear (poor scanner). However, i rechecked the diagram and that's how it is. I also find connecting the capacitor directly to the battery senseless too.

Thank you for your reply.
 

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