How Do You Calculate V_D in Terms of Circuit Components and Constants?

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SUMMARY

The discussion focuses on calculating the voltage drop, V_D, in terms of circuit components such as R_S, R_d, R_D, V_i, and the constant G. Participants emphasize the importance of applying circuit analysis techniques, specifically nodal and mesh analysis, to derive V_D effectively. The conversation highlights the necessity of accurately redrawing the circuit to visualize series and parallel resistor configurations, which aids in understanding the relationships between the components. The mention of constraints and external values, particularly V_i, is crucial for solving the equations involved.

PREREQUISITES
  • Understanding of circuit analysis techniques, specifically nodal and mesh analysis.
  • Familiarity with voltage and current divider rules.
  • Knowledge of resistor configurations, including series and parallel arrangements.
  • Basic grasp of circuit components such as voltage sources and current sources.
NEXT STEPS
  • Study the application of nodal analysis in circuit design.
  • Learn about mesh analysis and its advantages in solving circuit problems.
  • Review voltage and current divider principles in detail.
  • Explore the implications of external circuit values on voltage calculations.
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing and solving circuit problems will benefit from this discussion.

Rawl
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Homework Statement


circuits.png


Trying to come up with an equation of V_D in terms R_S, R_d, R_D, V_i, G

G is a constant

Homework Equations



Sum of voltages around a loop = 0
Sum of currents at a node = 0
Voltage divider
Current divider
Resistance of resistors in parallel

The Attempt at a Solution



<br /> V_i = V_D<br />

I'm not exactly sure but if you probe with your voltmeter from the ground to the upper side of V_D and then do the same at the top of the current source. Wouldn't those be the only two components in a loop?
 

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Hi Rawl, :welcome:

Not good you didn't receive an adequate reply yet, so I'll give it a go. The red thingy to me seems to represent a current source, but you forgot to mention that. G is not just a constant, it has a dimension too !

My advice is to redraw the circuit: source at left, the resistors to the right. resistors in series clearly shown in series and parallels visually parallel. Insight will come in a flash !

oh and perhaps upside down to see the relation between VD and Vis ... :rolleyes:
 
Looks like a two node or two loop problem. Either way, two equations in two unknowns with the constraints implied by the ##V_{is}## constraint equation. Since ##V_i## is not specified on the given circuit diagram it presumably is some external value that is part of some other circuit.

Both mesh and nodal methods have their own small advantages here: Nodal analysis would allow you solve for ##V_D## directly and "access" to ##V_S## for applying the constraint, while mesh analysis gives you the current in the small loop as "already solved", since it contains a current source. About the same amount of algebra for each, I'd guess. So pick an analysis method and write some equations.
 

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