How Do You Convert 2-Axis Rotation to 3-Axis Lift for a Disc?

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SUMMARY

This discussion focuses on converting 2-axis rotation (tilt in the x-direction \(\theta_x\) and y-direction \(\theta_y\)) into 3-axis lift for a disc mounted on three vertical pistons. The solution involves calculating the angles \(\alpha\) and \(\beta\) based on the tilt angles and the angle \(\Omega\) from the x-axis. The final approach requires measuring the average height of the three pistons and adjusting their heights accordingly to maintain the disc's center at a constant elevation.

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Homework Statement


Hi there,
In my experiment I have a disc which needs to be pitched and rolled about it's centre. The disk is mounted by three vertical "pistons" one every 120degrees. I need to convert a tilt in the x-direction \theta_x and a tilt in the y-direction \theta_y to how much each piston should be raised and lowered by. An additional constraint is that the centre of the disc must stay at the same height.
I've been bashing my head against a wall with this for what seems like forever and any help will be appreciated...

Homework Equations


We name the positioners A, B and C at height z_{a,b,c} and the angle from origin O to A is \alpha O to B as \beta and O to C \gamma.
The direction O to A is at an angle of \Omega to the x-axis.
The length of O to A is r.

The Attempt at a Solution


I figured out that
\alpha = \theta_x\cos\Omega + \frac{\sqrt{3}}{3}\sin\Omega+ \theta_y\frac{\sqrt{3}}{3}\cos\Omega-\theta_y\sin\Omega
and
\beta = \theta_x 2 \frac{\sqrt{3}}{3} \sin \Omega + \theta_y 2 \frac{\sqrt{3}}{3} \cos\Omega
From here I get stuck: I've tried many things but I know they're wrong (as in my experiment it doesn't work properly!)
Any help please, thanks in advance
 
Last edited:
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Solution found!
Measure the average height of the three points.
Use trig to move z_a and z_b.
Remeasure average height.
Move z_a, z_b and z_c all the difference between the two.
 

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