How Do You Convert Energy from J/kg to kJ/mol?

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Homework Help Overview

The discussion revolves around converting energy values from joules per kilogram to kilojoules per mole, specifically using a value of 553 x 10^5 J/kg. The subject area includes thermodynamics and stoichiometry related to energy calculations in chemistry.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the conversion of joules to kilojoules and the need for molecular weight to relate kilograms to moles. There are attempts to clarify the conversion process and the importance of knowing the material's molecular weight.

Discussion Status

Participants are actively engaging in the conversion process, with some providing guidance on how to approach the problem. There is recognition of the need for additional information regarding the molecular weight and its units. Multiple interpretations of the molecular weight are being explored, and some participants express uncertainty about the calculations.

Contextual Notes

There is a specific mention of kerosene with a molecular weight of 120, but participants question whether this is in grams per mole or kilograms per mole, indicating a potential source of confusion. The discussion also highlights the need for clarity on the relationship between mass and moles in the context of the problem.

clintyip
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Let's say I have a value of:

553 x 10^5 j/kg

How would I convert that to kJ/mol?
 
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mol = mass/molecular weight. = kg/M
kJ = 10^3 J
 
so that means if I had 55300000 j/kg, that would be 55300 kJ/kg.

How would I make it into kJ/mol...

(sorry, I'm not very good at converting...)
 
from J to kJ all you need to do is of course to divide in 1000 (=k).

It's simply to look at it like this:

10^3j = kj => j = 10^-3kj
so 553 * 10^5 j = 553 * 10^5 * 10^-3 kj = 553 * 10 ^2 kj
(I substituted j for kj using the upper formula).

About kg=>mol, well, for that you'll have to tell us what's the material involved.
Imagine there are plastic and metal balls. A plastic ball weighs 1 kg and a metal ball 2kg.
It'd be like asking you "how many balls are in a sack weighing 10kg?". If you knew it's plastic balls, you'd say 10. If it were metal balls, you'd say 5.

so 1kg can be 1000 mol and it can be 1 mol => we need more information.
 
Tomer said:
from J to kJ all you need to do is of course to divide in 1000 (=k).

It's simply to look at it like this:

10^3j = kj => j = 10^-3kj
so 553 * 10^5 j = 553 * 10^5 * 10^-3 kj = 553 * 10 ^2 kj
(I substituted j for kg using the upper formula).

About kg=>mol, well, for that you'll have to tell us what's the material involved.
Imagine there are plastic and metal balls. A plastic ball weighs 1 kg and a metal ball 2kg.
It'd be like asking you "how many balls are in a sack weighing 10kg?". If you knew it's plastic balls, you'd say 10. If it were metal balls, you'd say 5.

so 1kg can be 1000 mol and it can be 1 mol => we need more information.

Well, this is actually a fuel, Kerosene, with a molecular weight of 120...
 
Then use the relation given by rl.bhat and derive the connection between kg and mol. When you say 120, make sure if it's 120 g/mol or 120 kg/mol, and convert fittingly.
 
Tomer said:
Then use the relation given by rl.bhat and derive the connection between kg and mol. When you say 120, make sure if it's 120 g/mol or 120 kg/mol, and convert fittingly.

So I have 55300 kJ/kg

Assuming that my Molecular weight is 120g/mol...

Yeah, I have no idea. It seems like there's a missing variable to me :S
 
How come?

rl.baht wrote: mol = mass / molecular weight.

we want to know the connection between kg and mol. So assume you have 1kg material.
Step 1: convert your molecular weight from 120g/mol => X kg/mol (you do it :-)
Step 2: use rl.baht connection written above, instead of mass you have "kg", and instead of molecular weight you have what you've calculated on Step 1.
Step 3: from the formula of Step 2 isolate kg. You'll get something like kg = Y mol.
Step 4: substitute kg for mol in the expression you've got.

Give it a try, it's important and basic. If you won't make it I'll show you the way.
 
Tomer said:
How come?

rl.baht wrote: mol = mass / molecular weight.

we want to know the connection between kg and mol. So assume you have 1kg material.
Step 1: convert your molecular weight from 120g/mol => X kg/mol (you do it :-)
Step 2: use rl.baht connection written above, instead of mass you have "kg", and instead of molecular weight you have what you've calculated on Step 1.
Step 3: from the formula of Step 2 isolate kg. You'll get something like kg = Y mol.
Step 4: substitute kg for mol in the expression you've got.

Give it a try, it's important and basic. If you won't make it I'll show you the way.

Step One: 120g/mol => 0.12kg/mol
Step Two: mol = mass/molecular weight
= kg/0.12 = mol
kg = 0.12mol

So 55300kJ/0.12mol
= 460833 kJ/mol

Wow, that's a big number, did I do it right?
 
  • #10
hehe, the distance between the Earth and the sun in centimeters is also a big number and it's still true :-)
About the numbers - I really don't know about the 120 g/kg, you should make sure of that, but it seems you did it perfectly, great!
 
  • #11
Haha, thanks! :)
 
  • #12
clintyip said:
Step One: 120g/mol => 0.12kg/mol
Step Two: mol = mass/molecular weight
= kg/0.12 = mol
kg = 0.12mol

So 55300kJ/0.12mol
= 460833 kJ/mol

Wow, that's a big number, did I do it right?

1 kg of kerosene produces 55300 kJ of energy.
How much energy is produced by 0.120 kg? That is required energy per mol.
 

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