How do you derive this (E=v/d)?

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SUMMARY

The derivation of the equation E = v/d is established through the relationship between electric potential (V) and electric field (E). Electric potential is defined as the negative line integral of the electric field when the field and path are aligned. By substituting q in the equation V = k(q/d) with (Ed²)/k, where E is the electric field at a distance d from a charge q, the equation E = v/d is confirmed as a valid expression for electric potential difference.

PREREQUISITES
  • Understanding of electric potential and electric field concepts
  • Familiarity with the equation V = k(q/d)
  • Basic knowledge of calculus for line integrals
  • Concept of point charges and their influence on electric fields
NEXT STEPS
  • Study the derivation of electric potential from electric field using calculus
  • Explore the implications of the equation E = v/d in different electric field configurations
  • Learn about the role of Coulomb's law in calculating electric fields
  • Investigate the applications of electric potential in circuit theory
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Physics students, electrical engineers, and anyone studying electromagnetism who seeks to understand the relationship between electric potential and electric fields.

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How do you derive this (E=v/d)?
 
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aaaaa :biggrin: that sort of went over my head.

Can you do it with this relation -

V = k(q/d)

i.e potential difference at a distance d from a charged particle q of a unit charge brought from infinity.
 


There's something wrong with latex...its showing my old codes.
 


Yep got that --

In V = k(q/d) substitute q with (Ed2)/k (derived from E.F at a point from a source charge q)

Solve and you get it.
 

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