How Do You Determine Linear Transformations in R^2?

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Homework Help Overview

The discussion revolves around determining the linear transformation L in R², given specific mappings of vectors. The original poster presents a problem involving the transformation of the vector (7,5) based on its relationships with the vectors (1,2) and (1,-1).

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the idea of expressing (7,5) as a linear combination of the vectors (1,2) and (1,-1). There are discussions about setting up systems of equations to find the coefficients for this combination.

Discussion Status

Some participants provide guidance on how to approach the problem by suggesting the use of linear combinations, while others express confusion about the nature of the transformation and its linearity. There is a mix of interpretations regarding the application of linear combinations versus direct mappings.

Contextual Notes

Participants note the importance of understanding the linear operator L and its effects on the given vectors, with some emphasizing that the problem may not solely rely on linear combinations.

IntroAnalysis
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Homework Statement


If L((1,2)^T) = (-2,3)^T and L((1, -1)T) = (5,2)T determine L((7,5)T)


Homework Equations


If L is a linear transformation mapping a vector V into W, it follows:
L(v1 + v2) = L(v1) +L(v2) (alpha = beta = 1)
and
L (alpha v) = alpha L(v) (v = v1, Beta = 0)


The Attempt at a Solution


I've tried all kind of linear combinations, rotations and reflections, and I just can't get this one. Can someone give a hint?
 
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You first need to write out (7,5) as a linear combination of (1,2) and (1,-1), so you need to find constants a1 and a2 such that
<br /> a_1(1,2) + a_2(1,-1) = (7,5).<br />

Can you turn this into a system of simultaneous equations?
 
Here is another example. L(x) = vector x +x1 = (x1 + x1, x2 + x1)
So L(1,2)^T = (2, 3)^T and L(2, 3)^T = (4, 5). Therefore, the L(3, 4)^T = (6, 7)^T

We are not taking linear combinations of the first 2 vectors to arrive at the third vector.
 
I don't really understand your last post. Writing out the vector to which you are applying L as a linear combination of two other vectors works fine in this example with L(x_1, x_2) = (2x_1, x_1 + x_2):

<br /> a_1 (1,2) + a_2 (2,3) = (3,4)<br />

<br /> a_1 + 2a_2 = 3<br />
<br /> 2a_1 + 3a_2 = 4<br />

Solving this system, I get a1 = -1 and a2 = 2. Then

<br /> L(3,4) = L(-(1,2) + 2(2,3)) = -L(1,2) + 2L(2,3) = -(2,3) + 2(4,5) = (6,7)<br />

as you got before. You can apply the same method to the problem in your original post.
 
This is not a linear combination of two vectors. I need to show a linear operator that takes
(1,2) transposed to (-2, 3). And it takes (1, -1) transposed to (5, 2) transposed.

This is not a linear combination of (1, 2) and (1, -1) problem.
 
It is a linear combination of (1, 2) and (1, -1) problem. If

L((1,2)^{T}) = (-2, 3)^{T},

then what is

L \[ \left( \begin{array}{c}<br /> 1\\<br /> 2\end{array} \right)?
 
IntroAnalysis said:
This is not a linear combination of two vectors. I need to show a linear operator that takes
(1,2) transposed to (-2, 3). And it takes (1, -1) transposed to (5, 2) transposed.

This is not a linear combination of (1, 2) and (1, -1) problem.
It reduces to the latter problem because the operator L is linear. Take a look again at what spamiam did in his or her last post.
 
Thanks for the help.
I see now that 4(1,2)T + 3(1, -1)T = (7, 5)T

Therefore L(7,5)T = 4(-2, 3)T + 3(5, 2)T = (7, 18)T
 

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