MHB How Do You Estimate Sums Using the Euler-Mascheroni Constant?

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The discussion focuses on estimating the sum $$\sum_{n=1}^{1,000,000} \frac{1}{n}$$ using the Euler-Mascheroni constant ($\gamma = 0.57721566$). The user successfully calculated the upper bound as approximately 14.39272 when $\gamma$ is known. However, they seek guidance on estimating the sum without this constant. A hint provided suggests utilizing upper and lower Riemann sums for the integral of the function $1/x$ to approach the problem.

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Hi, question asks to set upper and lower bounds on $$\sum_{n=1}^{1,000,000} \frac{1}{n}$$ assuming (a) the Euler-Mascheroni constant is known and (b) not known.

$\gamma = \lim_{{n}\to{\infty\left( \sum_{m=1}^{n} \frac{1}{m} \right)}} = 0.57721566$ and I found (a) easily (14.39272...), but no idea how to approach part b, a hint please?

This is similar to another problem, a pocket calculator gives $ \sum_{1}^{100} \frac{1}{{n}^{-3}}= 1.202 $, find upper and lower limits? Probably the hint will cover both :-)
 
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ognik said:
Hi, question asks to set upper and lower bounds on $$\sum_{n=1}^{1,000,000} \frac{1}{n}$$ assuming (a) the Euler-Mascheroni constant is known and (b) not known.

$\gamma = \lim_{{n}\to{\infty\left( \sum_{m=1}^{n} \frac{1}{m} \right)}} = 0.57721566$ and I found (a) easily (14.39272...), but no idea how to approach part b, a hint please?

This is similar to another problem, a pocket calculator gives $ \sum_{1}^{100} \frac{1}{{n}^{-3}}= 1.202 $, find upper and lower limits? Probably the hint will cover both :-)
Hint: Use upper and lower Riemann sums for the integral of the function $1/x$, as in this picture:
 

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