MHB How Do You Evaluate and Differentiate Complex Trigonometric Functions?

Ivan1
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Evaluate ∫[sin2x/(1+(cos)^2 x) dx]Differentiate f(x) = (sin)^2 (e^((sin^2) x))

Hello, I'm just really stumped with these review questions and i have a test coming up. For the first, I'm not too sure what to do since there is a sin2x in general and for the second i don't know how to deal the the exponential. Some help would be really appreciated!
 
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Hello Ivan, welcome to MHB! (Wave)

When you are integrating, it is always helpful to first see if you can find a function and its derivative in the integrand. In this case, rewriting the integrand produces exactly what we want:
$$\int \frac{\sin\left({2x}\right)}{1+\cos^2\left({x}\right)} \,dx=\int \frac{2\sin\left({x}\right)\cos\left({x}\right)}{1+1-\sin^2\left({x}\right)} \,dx$$

For your derivative, do you mean this?
$$\sin^2\left({e^{\sin^2x}x}\right)$$

Recall that given a function $e^{f(x)}$, its derivative is $e^{f(x)}\cdot f'(x)$
 
Ivan said:
Evaluate ∫[sin2x/(1+(cos)^2 x) dx]Differentiate f(x) = (sin)^2 (e^((sin^2) x))
Just to be clear, are your questions
[math]\int \frac{\sin(2x)}{1 + \cos^2(x)}~dx[/math]

and
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]

-Dan
 
topsquark said:
Just to be clear, are your questions
[math]\int \frac{\sin(2x)}{1 + \cos^2(x)}~dx[/math]

and
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]

-Dan

Yes
 
Let's look at the first problem, and use a method similar to that suggested by Rido12:

$$\int\frac{\sin(2x)}{1+\cos^2(x)}\,dx$$

Now, if we let:

$$u=1+\cos^2(x)$$

then we find:

$$du=2\cos(x)(-\sin(x))\,dx=-\sin(2x)\,dx$$

Now, if we write the integral as:

$$-\int\frac{-\sin(2x)\,dx}{1+\cos^2(x)}$$

What does it become when we use our $u$-substitution?
 
topsquark said:
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]
Do this with the chain rule. I'll separate the different derivatives with [ ] symbols.
[math]f'(x) = \left [ 2~sin \left ( e^{\sin^2(x)} \right )~cos \left ( e^{\sin^2(x)} \right ) \right ] \cdot \left [ e^{\sin^2(x)} \right ] \cdot \left [ 2~sin(x)~cos(x) \right ] [/math]

-Dan
 

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