How Do You Evaluate and Differentiate Complex Trigonometric Functions?

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Discussion Overview

The discussion revolves around evaluating and differentiating complex trigonometric functions, specifically focusing on the integral of a trigonometric expression and the differentiation of a function involving an exponential and trigonometric components. The scope includes mathematical reasoning and technical explanations related to calculus.

Discussion Character

  • Mathematical reasoning
  • Technical explanation
  • Homework-related

Main Points Raised

  • One participant expresses confusion regarding the integral of \(\frac{\sin(2x)}{1+\cos^2(x)}\) and the differentiation of \(f(x) = \sin^2(e^{\sin^2(x)})\).
  • Another participant suggests rewriting the integrand to identify a function and its derivative, proposing a substitution method for the integral.
  • A later reply clarifies the specific questions regarding the integral and the function to be differentiated.
  • Further, a participant outlines a substitution approach for the integral, introducing \(u = 1 + \cos^2(x)\) and its corresponding differential.
  • For the differentiation, a participant provides a detailed expression using the chain rule, breaking down the components of the derivative.

Areas of Agreement / Disagreement

Participants generally agree on the formulation of the problems but do not reach a consensus on the methods or solutions for the integral and differentiation tasks. Multiple approaches and interpretations are presented without resolution.

Contextual Notes

Some assumptions regarding the methods of integration and differentiation are not explicitly stated, and the discussion does not resolve the mathematical steps involved in the proposed solutions.

Ivan1
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Evaluate ∫[sin2x/(1+(cos)^2 x) dx]Differentiate f(x) = (sin)^2 (e^((sin^2) x))

Hello, I'm just really stumped with these review questions and i have a test coming up. For the first, I'm not too sure what to do since there is a sin2x in general and for the second i don't know how to deal the the exponential. Some help would be really appreciated!
 
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Hello Ivan, welcome to MHB! (Wave)

When you are integrating, it is always helpful to first see if you can find a function and its derivative in the integrand. In this case, rewriting the integrand produces exactly what we want:
$$\int \frac{\sin\left({2x}\right)}{1+\cos^2\left({x}\right)} \,dx=\int \frac{2\sin\left({x}\right)\cos\left({x}\right)}{1+1-\sin^2\left({x}\right)} \,dx$$

For your derivative, do you mean this?
$$\sin^2\left({e^{\sin^2x}x}\right)$$

Recall that given a function $e^{f(x)}$, its derivative is $e^{f(x)}\cdot f'(x)$
 
Ivan said:
Evaluate ∫[sin2x/(1+(cos)^2 x) dx]Differentiate f(x) = (sin)^2 (e^((sin^2) x))
Just to be clear, are your questions
[math]\int \frac{\sin(2x)}{1 + \cos^2(x)}~dx[/math]

and
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]

-Dan
 
topsquark said:
Just to be clear, are your questions
[math]\int \frac{\sin(2x)}{1 + \cos^2(x)}~dx[/math]

and
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]

-Dan

Yes
 
Let's look at the first problem, and use a method similar to that suggested by Rido12:

$$\int\frac{\sin(2x)}{1+\cos^2(x)}\,dx$$

Now, if we let:

$$u=1+\cos^2(x)$$

then we find:

$$du=2\cos(x)(-\sin(x))\,dx=-\sin(2x)\,dx$$

Now, if we write the integral as:

$$-\int\frac{-\sin(2x)\,dx}{1+\cos^2(x)}$$

What does it become when we use our $u$-substitution?
 
topsquark said:
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]
Do this with the chain rule. I'll separate the different derivatives with [ ] symbols.
[math]f'(x) = \left [ 2~sin \left ( e^{\sin^2(x)} \right )~cos \left ( e^{\sin^2(x)} \right ) \right ] \cdot \left [ e^{\sin^2(x)} \right ] \cdot \left [ 2~sin(x)~cos(x) \right ] [/math]

-Dan
 

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