How Do You Evaluate and Differentiate Complex Trigonometric Functions?

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SUMMARY

This discussion focuses on evaluating the integral ∫[sin(2x)/(1+(cos)^2 x) dx] and differentiating the function f(x) = (sin)^2(e^(sin^2 x)). The integral is approached using u-substitution, where u = 1 + cos^2(x) and du = -sin(2x) dx, simplifying the evaluation process. For differentiation, the chain rule is applied, resulting in f'(x) = [2 sin(e^(sin^2(x))) cos(e^(sin^2(x)))] * [e^(sin^2(x))] * [2 sin(x) cos(x)].

PREREQUISITES
  • Understanding of integral calculus, specifically u-substitution.
  • Familiarity with differentiation techniques, including the chain rule.
  • Knowledge of trigonometric identities and functions.
  • Experience with exponential functions and their derivatives.
NEXT STEPS
  • Practice u-substitution in various integral problems.
  • Study the chain rule in differentiation with complex functions.
  • Explore trigonometric identities to simplify integrals and derivatives.
  • Learn about the properties of exponential functions and their applications in calculus.
USEFUL FOR

Students preparing for calculus exams, educators teaching integral and differential calculus, and anyone looking to strengthen their understanding of trigonometric functions and their applications in calculus.

Ivan1
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Evaluate ∫[sin2x/(1+(cos)^2 x) dx]Differentiate f(x) = (sin)^2 (e^((sin^2) x))

Hello, I'm just really stumped with these review questions and i have a test coming up. For the first, I'm not too sure what to do since there is a sin2x in general and for the second i don't know how to deal the the exponential. Some help would be really appreciated!
 
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Hello Ivan, welcome to MHB! (Wave)

When you are integrating, it is always helpful to first see if you can find a function and its derivative in the integrand. In this case, rewriting the integrand produces exactly what we want:
$$\int \frac{\sin\left({2x}\right)}{1+\cos^2\left({x}\right)} \,dx=\int \frac{2\sin\left({x}\right)\cos\left({x}\right)}{1+1-\sin^2\left({x}\right)} \,dx$$

For your derivative, do you mean this?
$$\sin^2\left({e^{\sin^2x}x}\right)$$

Recall that given a function $e^{f(x)}$, its derivative is $e^{f(x)}\cdot f'(x)$
 
Ivan said:
Evaluate ∫[sin2x/(1+(cos)^2 x) dx]Differentiate f(x) = (sin)^2 (e^((sin^2) x))
Just to be clear, are your questions
[math]\int \frac{\sin(2x)}{1 + \cos^2(x)}~dx[/math]

and
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]

-Dan
 
topsquark said:
Just to be clear, are your questions
[math]\int \frac{\sin(2x)}{1 + \cos^2(x)}~dx[/math]

and
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]

-Dan

Yes
 
Let's look at the first problem, and use a method similar to that suggested by Rido12:

$$\int\frac{\sin(2x)}{1+\cos^2(x)}\,dx$$

Now, if we let:

$$u=1+\cos^2(x)$$

then we find:

$$du=2\cos(x)(-\sin(x))\,dx=-\sin(2x)\,dx$$

Now, if we write the integral as:

$$-\int\frac{-\sin(2x)\,dx}{1+\cos^2(x)}$$

What does it become when we use our $u$-substitution?
 
topsquark said:
[math]f(x) = \sin^2 \left ( e^{\sin^2(x)} \right )[/math]
Do this with the chain rule. I'll separate the different derivatives with [ ] symbols.
[math]f'(x) = \left [ 2~sin \left ( e^{\sin^2(x)} \right )~cos \left ( e^{\sin^2(x)} \right ) \right ] \cdot \left [ e^{\sin^2(x)} \right ] \cdot \left [ 2~sin(x)~cos(x) \right ] [/math]

-Dan
 

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