How Do You Find the Center of Mass for a Non-Uniform Bar Using Calculus?

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SUMMARY

The discussion focuses on calculating the center of mass for a non-uniform bar with a mass distribution defined by the equation 0.6 + x² over a length of 2 meters. The correct mass of the bar is determined to be 2 kg through integration, yielding the integral 0.6x + x³/3 evaluated from 0 to 2. However, the initial approach to find the center of mass by equating the mass distribution to half the total mass is incorrect. The center of mass must account for the distribution of mass along the length of the bar, requiring a different method that considers leverage and the weighted average of the mass distribution.

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DLH112
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Homework Statement


find the mass of an unevenly distributed bar with length 2 meters whos mass at a point is given by an equation 0.6 + x^2. Then find the center of mass.


Homework Equations





The Attempt at a Solution


I got the first part (finding the mass) correctly, but I can't conceptually figure out why what i did to find the center of mass doesn't work.

integrate to get 0.6x + x^3/3 and evaluate from 0 to 2, to find that the mass is 2 kg.
What I tried to do to find the center of mass is just set that equation equal to half the mass and solve for X, however this is not correct and I do not know why...
 
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DLH112 said:

Homework Statement


find the mass of an unevenly distributed bar with length 2 meters whos mass at a point is given by an equation 0.6 + x^2. Then find the center of mass.

Homework Equations


The Attempt at a Solution


I got the first part (finding the mass) correctly, but I can't conceptually figure out why what i did to find the center of mass doesn't work.

integrate to get 0.6x + x^3/3 and evaluate from 0 to 2, to find that the mass is 2 kg.
What I tried to do to find the center of mass is just set that equation equal to half the mass and solve for X, however this is not correct and I do not know why...
The approach you used would be correct if you were trying to find the location where 1/2 the mass is to the left and the other other 1/2 is to the right. :smile:

But that's not what you're being asked to find. :frown:

Here, the term "center of mass" needs to take into account the leverage involved. Sometimes the term is also called the barycenter, center of gravity, weighted center or point of balance. You're looking for the point such that if you were to grab the object at that point with your fingers, it would balance.

I'm guessing that you might find a formula for the barycenter (center of mass) from your textbook. With that, you can simply plug and chug.

Or you could derive the formula yourself. If you define r as the distance from the barycenter xc to some small mass dm, then you need to set up an equation such that the sum of all r dm on one side of xc equals the sum of all r dm on the other side of xc. Then solve for xc.

Good luck! :smile:
 

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