How do you find the density of a liquid with a submerged block?

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To find the density of a liquid using a submerged block, the apparent mass of the block in the liquid is compared to its actual mass. The block's density is given as 8.90 g/cm^3, with an apparent mass of 120g in water and 116g in the unknown liquid. The formula m/(m-mapparent) = p/pliquid is used to derive the density of the liquid. The discussion highlights that articulating the problem can lead to clarity and potential solutions. Ultimately, the approach emphasizes the importance of understanding the relationship between mass, apparent mass, and density.
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Homework Statement


A block has a density of 8.90 g/cm^3 and has an apparent mass of 120g in water and 116g when submerged in a liquid. What is the density of the liquid?

Homework Equations


m/(m-mapparent) = p/pliquid

The Attempt at a Solution


Nevermind.
 
Last edited:
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Well done?
Sometimes just explaining the question will suggest the answer eh?
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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