- #1

Juggler123

- 83

- 0

0 if -[tex]\pi[/tex] [tex]\prec[/tex] x [tex]\leq[/tex] -[tex]\frac{\pi}{2}[/tex]

1+x if -[tex]\frac{\pi}{2}[/tex] [tex]\prec[/tex] x [tex]\prec[/tex] [tex]\frac{\pi}{2}[/tex]

0 if [tex]\frac{\pi}{2}[/tex] [tex]\leq[/tex] x [tex]\leq[/tex] [tex]\pi[/tex]

I've never done a Fourier series computation before so I don't really know if any of what I'm doing is correct.

I've got than a(0)=1, a(n)=[tex]\frac{2sin\frac{n\pi}{2}}{n\pi}[/tex] and

b(n)=[tex]\frac{2sin\frac{n\pi}{2}}{n^{2}\pi}[/tex] - [tex]\frac{cos\frac{n\pi}{2}}{n}[/tex]

I know the formula for a Fourier series but none of the examples I've seen are in the form of the a(n) and b(n) that I've got so I don't know where to go next.

Could anyone help please? Thankyou.