How do you find the initial velocity of a projectile given angle/distance?

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To find the initial velocity of a projectile given an angle and distance, it's essential to resolve the motion into vertical and horizontal components. The problem involves a ball thrown from a height of 30.0 m at an angle of 20.0° below horizontal, landing 29.3 m away. The key is to use the SUVAT equations to relate the variables of interest, including time, which connects horizontal and vertical motions. The initial velocity can be calculated by determining the time of flight and using the horizontal distance traveled. The user ultimately solved the problem independently after seeking assistance.
iamcgettigan
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Homework Statement
I am in 10th grade physics. The question is: A person standing on top of a 30.0 m high building throws a ball with an angle of 20.0° below horizontal. If the ball lands 29.3 m away from the building, what is the initial velocity of the ball? I know the answer is 16m/s, however I am unsure of how to arrive at this answer.
Relevant Equations
s=ut+½at^2
I tried resolving the information given into vertical and horizontal components. I then tried to find time, as this is how I would find the initial velocity. However, I am unsure of how to use the angle in this problem to help solve it. I am also unsure of how to find the initial velocity only given angle and distances. Any help would be greatly appreciated!
 
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iamcgettigan said:
Homework Statement:: I am in 10th grade physics. The question is: A person standing on top of a 30.0 m high building throws a ball with an angle of 20.0° below horizontal. If the ball lands 29.3 m away from the building, what is the initial velocity of the ball? I know the answer is 16m/s, however I am unsure of how to arrive at this answer.
Relevant Equations:: s=ut+½at^2

I tried resolving the information given into vertical and horizontal components. I then tried to find time, as this is how I would find the initial velocity. However, I am unsure of how to use the angle in this problem to help solve it. I am also unsure of how to find the initial velocity only given angle and distances. Any help would be greatly appreciated!
Please post your work as far as you get (and please, not as an image).

In the standard form of constant acceleration equations (SUVAT) there are five variables. Each equation relates four of them, so five equations for vertical motion. Horizontal is somewhat simpler.

The trick is to identify those variables which are of interest and choose your equations accordingly. Any variable you are given in the question and any variable you are asked to find is of interest. A variable which connects the horizontal and vertical motions (there is one here) is also relevant.
 
haruspex said:
Please post your work as far as you get (and please, not as an image).

In the standard form of constant acceleration equations (SUVAT) there are five variables. Each equation relates four of them, so five equations for vertical motion. Horizontal is somewhat simpler.

The trick is to identify those variables which are of interest and choose your equations accordingly. Any variable you are given in the question and any variable you are asked to find is of interest. A variable which connects the horizontal and vertical motions (there is one here) is also relevant.

Thank you for your response. I am sorry to have somewhat wasted your time as I have figured it out. Thanks again.
 
iamcgettigan said:
Thank you for your response. I am sorry to have somewhat wasted your time as I have figured it out. Thanks again.
That's fine - glad you got there by your own efforts.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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