How do you find time given vi, acceleration, and displacement

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SUMMARY

The discussion centers on solving the quadratic equation derived from the motion formula d=vit + 1/2at^2, specifically for the scenario where an object is dropped. The user substitutes values into the equation, resulting in 75 = 3t + 1/2 (9.81)t^2. The question arises regarding the sign of gravity, which is correctly noted as -9.81 m/s² when considering downward motion. The conversation emphasizes the importance of understanding quadratic equations to solve for time (t).

PREREQUISITES
  • Understanding of kinematic equations, specifically d=vit + 1/2at^2
  • Knowledge of quadratic equations and their solutions
  • Familiarity with gravitational acceleration, specifically -9.81 m/s²
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study methods for solving quadratic equations, including factoring and the quadratic formula
  • Learn about kinematic equations in physics and their applications
  • Explore the concept of gravitational acceleration and its effects on falling objects
  • Practice problems involving displacement, initial velocity, and acceleration
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in solving motion-related problems using quadratic equations.

xcfzm94
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using

d=vit+ 1/2at^2

my subs are

75 =3t +1/2 (9.81)t^2 (if an object is dropped is gravity still -9.81?)

where do i go from here
 
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