How Do You Form a Linear Equation for the Equipment's Value Over 10 Years?

AI Thread Summary
The school district's high-volume printer, copier, and scanner, initially valued at $24,000, will depreciate to $2,000 over 10 years. A linear equation to represent the equipment's value over time is derived as V = -2.2t + 24, where V is the value in thousands of dollars and t is the time in years. The slope of the equation indicates a decrease in value of $2,200 per year. The initial value at t = 0 is $24,000, confirming the y-intercept. This linear model effectively captures the equipment's depreciation over its useful life.
nycmathguy
Homework Statement
Write a linear equation representing the situation at hand.
Relevant Equations
y = mx + b
A school district purchases a high-volume printer, copier, and scanner for $24,000. After 10 years, the equipment will have to be replaced. Its value at that time is expected to be $2000. Write a linear equation giving the value V of the equipment during the 10 years it will be in use.

Let t = time

The general linear equation representing this situation is V = mt + b.

I will reduce 24,000/2,000 to the lowest terms.

24,000/2,000 becomes 24/2.

Slope = (change in V)/(change in t).

Slope = (2 - 24)/(10 - 0)

Slope = -20/10

Slope = -2.

I now go back to the general linear equation given above to plug -2 for m (the slope) and 24 for b (our y-intercept).

I say the equation is V = -2t + 24.

You say?
 
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I ask how much is it worth after 10 years?
 
nycmathguy said:
I say the equation is V = -2t + 24.
So the equipment is worth $24 at the beginning (at t = 0)?
 
nycmathguy said:
Slope = (2 - 24)/(10 - 0) = 2

I say the equation is V = -2t + 24.

You say?
Always Validate your answer.
you meant 22/10 = 2.2

for t= 10 , V=2, a = (2-24)/10 = -2.2 thus V = -2.2t+24 for units in [$k]
 
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